The answer is:
D. Ac = {xΙx ∈ U and is an even positive integer}
:)
Answer:
The equation of parabola is given by : ![(x-4) = \frac{-1}{3}(y+3)^{2}](https://tex.z-dn.net/?f=%28x-4%29%20%3D%20%5Cfrac%7B-1%7D%7B3%7D%28y%2B3%29%5E%7B2%7D)
Step-by-step explanation:
Given that vertex and focus of parabola are
Vertex: (4,-3)
Focus:(
,-3)
The general equation of parabola is given by.
, When x-componet of focus and Vertex is same
, When y-componet of focus and Vertex is same
where Vertex: (h,k)
and p is distance between vertex and focus
The distance between two points is given by :
L=![\sqrt{(X2-X1)^{2}+(Y2-Y1)^{2}}](https://tex.z-dn.net/?f=%5Csqrt%7B%28X2-X1%29%5E%7B2%7D%2B%28Y2-Y1%29%5E%7B2%7D%7D)
For value of p:
p=![\sqrt{(X2-X1)^{2}+(Y2-Y1)^{2}}](https://tex.z-dn.net/?f=%5Csqrt%7B%28X2-X1%29%5E%7B2%7D%2B%28Y2-Y1%29%5E%7B2%7D%7D)
p=![\sqrt{(4-\frac{47}{12})^{2}+((-3)-(-3))^{2}}](https://tex.z-dn.net/?f=%5Csqrt%7B%284-%5Cfrac%7B47%7D%7B12%7D%29%5E%7B2%7D%2B%28%28-3%29-%28-3%29%29%5E%7B2%7D%7D)
p=![\sqrt{(\frac{1}{12})^{2}}](https://tex.z-dn.net/?f=%5Csqrt%7B%28%5Cfrac%7B1%7D%7B12%7D%29%5E%7B2%7D%7D)
p=
and p=![\frac{-1}{12}](https://tex.z-dn.net/?f=%5Cfrac%7B-1%7D%7B12%7D)
Since, Focus is left side of the vertex,
p=
is required value
Replacing value in general equation of parabola,
Vertex: (h,k)=(4,-3)
p=
![(x-h) = 4p(y-k)^{2}](https://tex.z-dn.net/?f=%28x-h%29%20%3D%204p%28y-k%29%5E%7B2%7D)
![(x-4) = 4(\frac{-1}{12})(y+3)^{2}](https://tex.z-dn.net/?f=%28x-4%29%20%3D%204%28%5Cfrac%7B-1%7D%7B12%7D%29%28y%2B3%29%5E%7B2%7D)
![(x-4) = \frac{-1}{3}(y+3)^{2}](https://tex.z-dn.net/?f=%28x-4%29%20%3D%20%5Cfrac%7B-1%7D%7B3%7D%28y%2B3%29%5E%7B2%7D)
Dogs : 18
i hope this answer was correct (:
Answer:
Step-by-step explanation:
HE LIKE HE LIKE........ABRYS OOOOOOOOOOOO
<span>he box plots below show attendance at a local movie theater and high school basketball games:
two box plots shown. The top one is labeled Movies. Minimum at 60, Q1 at 65, median at 95, Q3 at 125, maximum at 150. The bottom box plot is labeled Basketball games. Minimum at 90, Q1 at 95, median at 125, Q3 at 145, maximum at 150.
Which of the following best describes how to measure the spread of the data?
The IQR is a better measure of spread for movies than it is for basketball games.
The standard deviation is a better measure of spread for movies than it is for basketball games.
The IQR is the best measurement of spread for games and movies.
The standard deviation is the best measurement of spread for games and movies.</span>