Diameter of a circle is two units. What is the radius of the circle?

Which inequality has the solution shown?

juin [17]

The answer should be d

5 0

2 years ago

A dog walker charges a flat rate of $6 per walk plus an hourly rate of $30. How much does the dog walker charge for a 45 minute

zvonat [6]

Step 1

Find the equation in function notation

Let

h-------> the number of hours

y-------> the function for the walker fee in dollars

we know that

the hourly rate is $30\frac{\$}{hour}$

$y=6+30h$

in this linear equation

the independent variable is the variable h

the dependent variable is the variable y

Convert to function notation

Let

$f(h)=y$

$f(h)=6+30h$

Step 2

Find how much does the dog walker charge for a 45 minute walk

Convert the time in hours

$1\ hour=60\ minutes$

$45\ minutes=45/60=0.75\ hours$

substitute in the equation

For $h=0.75\ hours$

$f(0.75)=6+30*(0.75)=\$28.5$

therefore

the answer is

the dog walker charge for a 45 minute walk $\$28.5$

Statements

Step 3

The dependent variable is the number of hours true or false

The statement is false,

because the independent variable is the number of hours and the dependent variable is the walker fee in dollars

Step 4

The function for the walker fee is f(h)= 30h+6 true or false

The statement is True --------> see the Step 1

Step 5

The dog walker charges $22.5 for a 45 min walk true or false

The statement is False

Because the dog walker charges for a 45 minute walk $\$28.5$

5 0

3 years ago

I need the answer fast please

Rainbow [258]

Substitute each value of x in y=2x-3

so,

first box (-2)
y= 2(-2)-3
y= -4-3
y= -7

second box (0)
y= 2(0)-3
y= 0-3
y= -3

third box (3)
y=2(3)-3
y=6-3
y=3

6 0

2 years ago

Read 2 more answers

Solve 12^x^2+5x-4 = 12^2x+6

faust18 [17]

The solutions for ‘x’ are 2 and -5

Step-by-step explanation:

Given equation:

$12^{x^{2}+5 x-4}=12^{2 x+6}$

Since the base on both sides as ‘12’ are the same, we can write it as

$x^{2}+5 x-4=2 x+6$

$x^{2}+5 x-2 x-4-6=0$

$x^{2}+3 x-10=0$

Often, the value of x is easiest to solve by $a x^{2}+b x+c=0$ by factoring a square factor, setting each factor to zero, and then isolating each factor. Whereas sometimes the equation is too awkward or doesn't matter at all, or you just don't feel like factoring.