Answer:
The statement that cushion A is twice as popular as cushion B cannot be verified
Step-by-step explanation:
From the question we are told that:
Sample size n=38
Type a size A 
Type a size B
Generally the probability of choosing cushion A P(a) is mathematically given by


Generally the equation for A to be twice as popular as B is mathematically given by

Therefore Hypothesis

Generally the equation normal approx of p value is mathematically given by



Therefore from distribution table


Therefore there is no sufficient evidence to disagree with the Null hypothesis 
Therefore the statement that cushion A is twice as popular as cushion B cannot be verified
So what it is asking you to do is compare the amount of oats to the other ingredients. ex, 2 cups of oats for every 0.5 cup of quinoa. just do that for the rest of them
Answer:
Step-by-step explanation:
d = c/pi
so d = 62.8/pi
d = 62.8/pi or appr 19.99in
r = d/2
so r = 62.8/2pi or 31.4/pi appr 19.99/2

so

then

so
a = approximately 313.84
answer is rowan
Answer:
Her error was multiplying numerator by numerator ( that is Quantity of Bone-shaped treats)
Step-by-step explanation:
Sarah's calculation
Let
x = cost of 12 Bone-shaped treats
Quantity of Bone-shaped treats : price
5 : 3.5 = 12 : x
(5/3.5) = (12/x)
Cross product
3.5x=60 (Here is her error)
x=17.14
Correct calculation
Quantity of Bone-shaped treats : price
5 : 3.5 = 12 : x
5 / 3.5 = 12 / x
Cross product
5 * x = 3.5 * 12
5x = 42
x = 42 / 5
= 8.4
x = $8.4
Her error was multiplying numerator by numerator ( that is Quantity of Bone-shaped treats)
Instead of multiplying Quantity of Bone-shaped treats by cost
Answer:
(4,5)
Step-by-step explanation:
(xa+xb/2,ya+yb/2)
(0+8/2,2+8/2)
(8/2,10/2)
(4,5)
hope this helps