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Tamiku [17]
3 years ago
11

All circuits must have three things: energy source, wire, and a generator

Physics
1 answer:
Colt1911 [192]3 years ago
4 0

Answer:

True

<h3><u>MORE</u><u> </u><u>TO</u><u> </u><u>KNOW</u><u> </u></h3>

  • A continuous and closed path of an electric current is called an <em><u>Circuit</u></em>

  • If the circuit is broken anywhere the current stop flowing

  • Components used in circuit are An electric cell , Battery, Switch , Wire , Bulb, Resistor

  • The direction of an electric current in a circuit is taken as opposite to the direction of flow of electrons

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What happens to the momentum of an object when velocity is kept the same and the mass is increased?
Jet001 [13]
Momentum = mass x velocity so if velocity is kept same and mass is increased then momentum will increase.
6 0
4 years ago
Which are properties of both a gas and a plasma
viktelen [127]

A plasma is an ionized gas , a gas into which sufficient energy is provided to free electrons from atoms or molecules and to allow both species , ions and electrons to coexist , Gases can become plasma in several ways , but all include pumping the gas with energy,

8 0
3 years ago
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Water drops from the nozzle of a shower onto the floor 81 inches below. The drops fall at regular intervals of time, the first d
Alexxx [7]

Answer:

0.91437 m

0.22859 m

Explanation:

g = Acceleration due to gravity = 9.81 m/s² = a

s=81\ inches=81\times 0.0254=2.0574\ m

s=ut+\frac{1}{2}at^2\\\Rightarrow 2.0574=0t+\frac{1}{2}\times 9.81\times t^2\\\Rightarrow t=\sqrt{\frac{2.0574\times 2}{9.81}}\\\Rightarrow t=0.64764\ s

When the time intervals are equal, if four drops are falling then we have 3 time intervals.

So, the time interval is

t'=\dfrac{t}{3}\\\Rightarrow t'=\dfrac{0.64764}{3}\\\Rightarrow t'=0.21588\ s

For second drop time is given by

t''=2t'\\\Rightarrow t''=2\times 0.21588\\\Rightarrow t''=0.43176\ s

Distance from second drop

s=ut+\dfrac{1}{2}at^2\\\Rightarrow y''=ut''+\dfrac{1}{2}at''^2\\\Rightarrow s=0\times t+\dfrac{1}{2}\times 9.81\times 0.43176^2\\\Rightarrow s=0.91437\ m

Distance from second drop is 0.91437 m

Distance from third drop

s=ut+\dfrac{1}{2}at^2\\\Rightarrow y''=ut'+\dfrac{1}{2}at'^2\\\Rightarrow s=0\times t+\dfrac{1}{2}\times 9.81\times 0.21588^2\\\Rightarrow s=0.22859\ m

Distance from third drop is 0.22859 m

6 0
3 years ago
Which is younger, the rock layers or the fault?
jeka94
<h2>FAULT</h2>

The principle of cross-cutting relationships states that a fault or intrusion is younger than the rocks that it cuts. The fault labeled 'E' cuts through all three sedimentary rock layers (A, B, and C) and also cuts through the intrusion (D). So the fault must be the youngest formation that is seen.

<em>-</em><em> </em><em>BRAINLIEST</em><em> answerer</em>

6 0
3 years ago
Read 2 more answers
A piece of rocky debris in space has a semi major axis of 45.0 AU. What is its orbital period?
KATRIN_1 [288]

Complete Question

Planet D has a semi-major axis = 60 AU and an orbital period of 18.164 days. A piece of rocky debris in space has a semi major axis of 45.0 AU.  What is its orbital period?

Answer:

The value  is  T_R  = 11.8 \  days  

Explanation:

From the question we are told that

   The semi - major axis of the rocky debris  a_R = 45.0\  AU

   The semi - major axis of  Planet D is  a_D  = 60 \  AU

    The orbital  period of planet D is  T_D = 18.164 \  days

Generally from Kepler third law

          T \  \ \alpha \ \ a^{\frac{3}{2} }

Here T is the  orbital period  while a is the semi major axis

So  

        \frac{T_D}{T_R}  =  \frac{a^{\frac{3}{2} }}{a_R^{\frac{3}{2} }}

=>     T_R  = T_D *  [\frac{a_R}{a_D} ]^{\frac{3}{2} }  

=>     T_R  = 18.164  *  [\frac{ 45}{60} ]^{\frac{3}{2} }

=>      T_R  = 11.8 \  days  

   

7 0
3 years ago
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