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kati45 [8]
3 years ago
7

Block 1, of mass m1

Physics
1 answer:
musickatia [10]3 years ago
7 0

Answer:

M2=0.52kg

Explanation:

thats rightt

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In telecommunication systems, Carrier frequency is a technical term used to indicate: ... The frequency of the unmodulated electromagnetic wave at the output of a conventional amplitude-modulated (AM-unsupressed carrier), or frequency-modulated (FM), or phase-modulated (PM) radio transmitter.
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Answers the questions <br> 1. At what distance did the object start to move ?
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A car is on a circular off ramp of an interstate and is traveling at exactly 25 mph around the curve. Does the car have velocity
netineya [11]

Answer:

The car has velocity and acceleration but is not decelerating

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Since the car is traveling at 25 mph around the curve, it has a tangential velocity. This tangential velocity is constantly changing in direction (so the car could adapt to the curve and not moving forward in a straight line), there should be a centripetal acceleration in play here. This acceleration does not slow down the car so it's not decelerating.

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A metal rod 80cm long lengthens by 0.090cm when its temperature rises by 93.6$^o$C. What is the linear expansivity of the metal
alexandr1967 [171]

Answer: (b)0.000012/k

Explanation:

The linear expansion of the metal rod is given by

\Delta L= L_0 \alpha \Delta T

where

\Delta L=0.090 cm is the linear expansion

L_0 = 80 cm is the initial length of the rod

\alpha is the linear expansivity

\Delta T=93.6^{\circ}C=93.6 K is the increase in temperature

By re-arranging the equation, we find the linear expansivity:

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8 0
4 years ago
A large helium filled balloon is used as the center piece for a graduation party. The balloon alone has a mass of 225 kg and it
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To solve this problem it is necessary to apply the concepts related to Newton's second law, the definition of density and sum of forces in bodies.

From Newton's second law we understand that

F= ma (\rightarrow Gravity at this case)

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m = mass

a= acceleration

Also we know that

\rho = \frac{m}{V} \Rightarrow m = \rho V

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F_b = ma

As mass is equal to the density and Volume and acceleration equal to Gravity constant

F_b = \rho V g

F_b = 1.2*323*9.8

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F_{net} = F_b -W

F_{net} = F_b -(mg+\rho_H Vg)

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4 years ago
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