What is the potential energy of a 2,000-kg car parked at the top of a 30-m hill?

2 answers:

5 0

Potential energy is a relative measure, so the answer is dependent on the assumptions we make. The potential energy in the car is going to be gravitational potential energy(PE). PE = mgh, where m is the mass, g is 9.8 m/s^2, and h is the height. So PE = 2000*9.8*h = 19600h. The final answer obviously depends on h. Most likely the problem is assuming that 30 meters under the top of the hill is considered 0 meters. Then h would be 30m and PE would equal 588 kJ.

vampirchik [111]3 years ago

5 0

Answer:

the answer is 588,000 J

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The contraction of muscles in the stomach walls

soldi70 [24.7K]

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8 0

3 years ago

In reaching her destination, a backpacker walks with an average velocity of 1.34 m/s, due west. This average velocity results be

Ivanshal [37]

We can define average velocity as:

av = (total distance travelled)/(total time)

Only using the above equation, we will find that she walked 807.3m due east.

The given information is:

The average velocity is 1.34 m/s due west.

(we can define west as the positive side and east as the negative side).

We know that first, she hikes 6.44km due west with an average velocity of 2.68 m/s.

To get the total time it took we write the equation:

2.68 m/s = (6,440m)/(time)

time = 6,440m/(2.68 m/s) = 2,402.9 seconds.

Then she hikes a distance D due east with an average velocity of 0.447 m/s, because she goes due east, we will write -D in the equations.

Now using the same equation as before, we can get the time as:

time' = -D/(-0.447 m/s) = D/(0.447 m/s)

Now the equation for the total average velocity will be:

1.34 m/s = (6,440m - D)/(2,402.9 s + D/(0.447 m/s))

Now we need to solve this for D.

(1.34 m/s)*(2,402.9 s + D/(0.447 m/s)) = (6,440m - D)

(1.34 m/s)*(2,402.9 s) + (1.34 m/s)*(D/(0.447 m/s) =6,440m - D

(1.34 m/s)*(D/(0.447 m/s) + D = 6,440m - (1.34 m/s)*(2,402.9 s) = 3,229.1 m

D*(1 + (1.34m/s)/(0.447 m/s)) = 3,229.1 m

D*4 = 3,229.1 m

D = 3,229.1 m/4 = 807.3 m

We can conclude that she walked 807.3m due east.

If you want to learn more, you can read:

brainly.com/question/862972

8 0

3 years ago

Read 2 more answers

A river 1.00 mile wide flows with a constant speed of 1.00 mph. A man can row a boat at 2.00 mph. He crosses the river in a dire

gladu [14]

To solve this problem we will apply the geometric concepts of displacement according to the description given. Taking into account that there is an initial displacement towards the North and then towards the west, therefore the speed would be:

$V_T^2=v_N^2-v_W^2$