Answer:
0.334 m
Explanation:
The magnetic field due to current in a straight thin wire, 
, is given by
where 
is the permeability of free spave with value 
and 
is the distance from the wire.
Substituting the values from the question,
Answer:
The downward force of gravity and the force exerted by the air.
Explanation:
Gravity, in a Newtonian Framework, acts at distance, so, the ball doesn't has to be connected to Earth to feel its gravitational pull (as we know by experience).
The racket only can exert a force in the ball when is touching it, so, once the ball has left the contact with the racket, there is no force by the "hit".
The air is always touching the ball on the atmosphere (even when physicist pretend that is not). So, there is drag from the wind, and a buoyant force exerted by the air over the ball at every time.
X = total horizontal distance = 25 ft
Y = total vertical distance = 125 ft
x = horizontal distance = 1 ft
y = vertical distance = ?
using the equation
y = (Y/X) (x)
inserting the values
y = (125/25) (1)
y = 5 ft
hence for each horizontal foot, the average height change is 5 ft
or
25 ft horizontal distance traveled = 125 ft vertical distance dropped
dividing both side by 25
25 ft horizontal distance traveled/25 = 125 ft vertical distance dropped/25
1 foot horizontal distance traveled = 25 ft vertical distance dropped
Answer:
P = density (p) * g * h
P = 1000 kg/m^3 * 9.8 m/s^2 * 40 m = 392,000 N/m^2
since kg m / s^2 = Newtons
The average pressure is 1/2 (pressure at 0m + pressure 80 m) for liquid of uniform density
