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SVETLANKA909090 [29]
3 years ago
14

The density of a mineral is determined by its mass and

Physics
1 answer:
My name is Ann [436]3 years ago
8 0

Answer: specific gravity

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Jack and Jill are maneuvering a 3100 kg boat near a dock. Initially the boat's position is < 2, 0, 3 > m and its speed is
liraira [26]

Answer:

(a) work done by Jack is -2200J

(b) work done by Jill is 0

Explanation:

Given;

Initially boat's position =  < 2, 0, 3 > m

Final boat's position = < 6, 0, 1 > m

change in position = < 4, 0, -2 >

Force exerted by Jack =  < -440, 0, 220 > N

Force exerted by Jill = < 170, 0, 340 > N

Part (a) How much work does Jack do?

work done = force x distance

Jack's work = < -440, 0, 220 > N x < 4, 0, -2 > m

                    = [(-440*4) + (0*0) + (220*-2)]

                    = -1760 J - 440 J

                    = -2200J

Part (b) How much work does Jill do?

Jill's work = < 170, 0, 340 > N x < 4, 0, -2> m

                 = [(170*4) + (0*0) + (340*-2)]

                  = 680 J - 680 J

                   = 0

7 0
4 years ago
Another term for electromotive force is _____.<br><br> voltage<br> current<br> resistance<br> power
Ray Of Light [21]
Voltage because I said so
3 0
3 years ago
Choose which best describes the following argument:
DaniilM [7]

Answer: The answer is a

Explanation:

5 0
3 years ago
Read 2 more answers
Two blocks with rough surfaces are stacked on top of a slippery horizontal surface. The top block has a mass of m, and the botto
lapo4ka [179]

Answer:

Please refer to the attached schematic for free-body diagrams of the blocks.

The contact forces N1 = mg, N2 = 3mg.

The friction force fs = mg/2.

The tension force T = 3mg/2.

The distance y = (gt^2)/4

Explanation:

Starting with the third block which is declining a time t. Newton's Second Law implies that

F = (3m)a\\3mg - T = 3ma\\T = 3mg - 3ma

There are two unknowns in one equation: T and a. Therefore, we need to find more equations to solve these unknown variables.

Let's look at free-body diagram 1:

Newton's Second Law:

F = ma\\f_s = ma

That is another equation with one more unknown: fs.

Free-body diagram 2:

F = (2m)a\\T - f_s = 2ma

That is our third equation. We now have three equations with three unknowns. Combining equation 2 and 3 gives:

T - ma = 2ma\\T = 3ma

Plugging this equation into the first equation gives

T = 3mg - 3ma\\3ma = 3mg - 3ma\\3mg = 6ma\\a = g/2

Following this, we can find the other unknowns:

T = 3ma = 3m(g/2) = \frac{3mg}{2}

f_s = ma = mg/2

The contact forces are N1 and N2.

N_1 = mg\\N_2 = 2mg + N1 = 3mg

Finally, using the acceleration and equation of kinematics, we can find the distance the hanging weight drops in a time t.

y - y_0 = v_0t + \frac{1}{2}at^2\\y = \frac{1}{2}(\frac{g}{2})t^2 = \frac{gt^2}{4}

6 0
4 years ago
A pair of shoes has a mass of .5kg. How much do they weigh on earth?
Masteriza [31]

Answer:

4.9 N

Explanation:

3 0
3 years ago
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