The force of the truck on the car is equal to the force of the car on the truck.
<h3>What is Newton's third law of motion?</h3>
- Newton's third law of motion states that action and reaction are equal and opposite.
Let the mass of the small car = m
Let the mass of the truck = M
The force exerted by the small car is calculated as;
F₁ = ma
The force exerted by the large truck is calculated as;
F₂ = Ma
According to Newton's third law, the magnitude of the two forces are equal but opposite in direction.
|F₁| = |F₂|
Thus, we can conclude that, the force of the truck on the car is equal to the force of the car on the truck.
Learn more about Newton's third law of motion here: brainly.com/question/25998091
Answer:
Vp = 1 [m/s]
Explanation:
In order to solve this problem, we must use the principle of conservation of the amount of movement. In the same way, analyze the before and after of the actions.
<u>The moment before</u>
The 50kg person is still hold (no movement) with the 2kg helmet
<u>The moment after</u>
The helmet moves at 25[m/s] in one direction, the person moves in the opposite direction, due to the launch of the helmet.
In this way we can apply the principle of conservation of movement, expressing the before and after. To the left we have the before and to the right of the equal sign we have the after.
Σm*V1 = Σm*V
where:
m = total mass = (2 + 50) = 52[kg]
V1 = velocity before the lunch = 0
(50 + 2)*V1 = (25*2) - (Vp*50)
0 = 50 - 50*Vp
50 = 50*Vp
Vp = 1 [m/s]
The answer is false! Hope that helps! :)
I believe L waves arrive last at a seismometer.
hope this helps!
the most appropriate answer is A !! our mind automatically connects everything and thus make a story that we don't even familiar with in actual !!
