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2 years ago

PLS HELP I WILL GOVE YOU TUE BRAINLIEST HELP PLSSS HIRRY PLS TY

Mathematics

2 answers:

damaskus [11]2 years ago

8 0

I tried answering it with the picture. I hope this helps!

vodka [1.7K]2 years ago

4 0

Answer: 180

Step-by-step explanation:

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The sum of two numbers is 90. Their difference is 18. Find the numbers.

Naddik [55]

Answer:

36 & 54

Step-by-step explanation:

By Question :-

Sum of numbers = 90 .
Difference of numbers = 18 .

Let :-

First Number be x .
Second number be y .

According to 1st condition :-

$: \implies$ x + y = 90

According to 2nd condition :-

$: \implies$ x - y = 18

Adding the equations :-

$: \implies$ 2x = 18 + 90

$: \implies$ 2x = 108

$: \implies$ x = 54

Therefore :-

$: \implies$ First number = 54

$: \implies$ Second number = 36

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2 years ago

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Can you answer this one

qaws [65]

Answer:

P'(-6,-4)

Step-by-step explanation:

By translating the point under the translation, to put it into a simpler form, it says to move the point 4 units to the left and 6 units down. Using this, the point will move to P'(-6,-4)

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3 years ago

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Which equation represents the graph. Please help I’m trying to finish a post test for math

8090 [49]

Answer:

5(x+3) is your answer

Step-by-step explanation:

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3 years ago

A builder wants to build the bridge whose cross section is shown in the diagram. Two companies offer simple bids on building the

leva [86]

The length of the bridge is the distance from the beginning to the end.

The distance b between each beam is 9ft.

Let:

$I \to$ I-Beam

$d_I \to$ distance between I beam and the bridge

$b \to$ distance between each I beam

Given that:

$I = \frac 34 ft\\$

$d_I = 3 ft$

$Length = 55ft\ 6in$ --- length of the bridge

From the diagram (see attachment), there are: 6 I-beams.

So, the length of the 6 I-beams is:

$L_1 = 6 \times I$

$L_1 = 6 \times \frac 34$

$L_1 = \frac {18}4$

$L_1 = 4.5ft$

There are 2 I-beams beside the bridge

So, the distance between the 2 I-beams and the bridge is:

$d_1 =2 \times d_I$

$d_1 =2 \times 3ft$

$d_1 =6ft$

There are 5 spaces between the I-beams

So, the length of the total spaces is:

$L_2 = 5 \times b$

$L_2 = 5b$

The total length is:

$Length = L_1 + d_1 + L_2$

So, we have:

$4.5ft + 6ft + 5b = 55ft\ 6in$

Collect like terms

$5b = 55ft\ 6in - 4.5ft - 6ft$

$5b = 44.5ft\ 6in$

Convert inches to feet

$5b = 44.5ft\ + \frac{6}{12}ft$

$5b = 44.5ft\ + 0.5ft$

$5b = 45ft$

Divide both sides by 5

$b = 9ft$

Hence, the distance (b) between each beam is 9ft.