Answer:
Im not sure about Q1 but I'll help with Q2
9 =

8 =
![\sqrt[3]{512}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B512%7D%20)
14 =

2 =
![\sqrt[3]{8}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B8%7D%20)
4 =

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Answer:
x² - 3x + 5 - [24÷(x+3)]
Step-by-step explanation:
1. Expand (x³ + 2x - 6x - 9)
= x³ - 4x - 9
2. Divide [x³ - 4x - 9 by x+3]
= x² + [(-3x^2-4x-9) ÷ (x+3)]
3. Divide [(-3x^2-4x-9) by (x+3)]
= -3x + [(5x-9) ÷ (x+3)]
x² - 3x + [(5x-9) ÷ (x+3)]
4. Divide [(5x-9) ÷ (x+3)]
= 5 + [(-24) ÷ (x+3)]
x² - 3x + 5 + [(-24) ÷ (x+3)]
= x² - 3x + 5 - [24 ÷ (x+3)]
Answer:
see below
Step-by-step explanation:
The mapping tells you how to find the vertices of the image:
(x, y) ⇒ (x +2, y -3)
S(-3,-2) ⇒ S'(-3 +2, -2 -3) = S'(-1, -5) . . . . . matches choice D
T(-4, 3) ⇒ T'(-4 +2, 3 -3) = T'(-2, 0)
V(-2, 3) ⇒ V'(-2 +2, 3 -3) = V'(0, 0)
Answer:
B
Step-by-step explanation:
2x+8=9
you want to isolate the variable so you subract 8 from both sides
2x=1
now you want x by itself so you divide by 2 on both sides
x=1/2 or x=0.5
Hope this helped :)
The second one they do not have to pass trough (0,0)