A kickball is a sphere, so to solve this, we are going to use the formula for the volume of a sphere:
![V= \frac{1}{6} \pi d^3](https://tex.z-dn.net/?f=V%3D%20%5Cfrac%7B1%7D%7B6%7D%20%20%5Cpi%20d%5E3)
where
![V](https://tex.z-dn.net/?f=V)
is the volume of the sphere.
![d](https://tex.z-dn.net/?f=d)
is the diameter of the sphere.
We know form our problem that the diameter of the kickball is 10 inches; since the kickball is a sphere,
![d=10in](https://tex.z-dn.net/?f=d%3D10in)
. Lets replace that value in our formula to find
![V](https://tex.z-dn.net/?f=V)
:
![V= \frac{1}{6} \pi d^3](https://tex.z-dn.net/?f=V%3D%20%5Cfrac%7B1%7D%7B6%7D%20%5Cpi%20d%5E3)
![V= \frac{1}{6} \pi (10in)^3](https://tex.z-dn.net/?f=V%3D%20%5Cfrac%7B1%7D%7B6%7D%20%5Cpi%20%2810in%29%5E3)
![V=523.6in^3](https://tex.z-dn.net/?f=V%3D523.6in%5E3)
We can conclude that the volume of the kickball is
523.6 cubic inches.
Answer:
The linear equation is y = 10 x
Step-by-step explanation:
Hi, to answer this question we have to analyze the information given:
- Rise rate = 10 ft per second
For each unit of time, we get ten units of height.
So, the linear equation is
y = 10 x
Where "y" is the height of the balloon after "x" seconds.
If we replace the variable x for a value we obtain the height.
For example, after 1 second:
y = 10 ft / sec x 1 sec
y = 10 feet
Feel free to ask for more if needed or if you did not understand something.
Answer:
Experimental unit = Oat
Response variable = Oat yield
Factors : Oat varieties ; Manure Concentration
Level of factors :
Oat = 3 levels
Manure concentration = 4 levels
Step-by-step explanation:
The experimental unit in this scenario is Oat, as it is the material or entity which we wish to research or learn about.
The response variable is what we intend to measure about the experimental unit, which is the yield of oat.
Factors here are the varieties of oat and the concentration of Manure which are the entities responsible for changes in the output or behavior of the dependent variable.
Level of factors : the different varieties of the factor variable, we have three Oat levels and 4 different Manure concentration levels.
Answer:
3780 bolts will be made by 8pm
Step-by-step explanation:
One Hour : 500 nuts or 840 bolts
Divide by 2
30 minutes : 250 nuts or 420 bolts
750 nuts : 500 + 250 = 750
so the machine took 1 hour and 30minutes
14:00 it started (2pm)
15:30 it switched to bolts
20:00 (8pm)
4 hours and 30minutes to get to 8pm
<u>840 × 4 = 3360 bolts + 420 bolts = 3780 bolts was made</u>