To know how many liters of water Bao use per liter of flour we have to divide the liters or flour so:
So Bao uses 0.33 or 1/3 of water per liter or flour
and to know hoy manu liters of flour Bao use per liter of water we have to made the oposite division so:
She use 3 liters of flour per liter of water
Answer:
C. $824.74, $175.26
Step-by-step explanation:
1) Amount Credited
The formula to calculate the amount credited =
Amount paid ÷ ( 100% - Discount)
Discount is given in the question as 3/10
Where 3 = Discount rate
Amount paid = $800
Amount credited = 800/( 100% - 3%)
= 800/ 97%
= 800/ 0.97
= $824.74
b) Outstanding balance = Invoice - Amount credited
Invoice = $1000
Amount credited = $824.74
Outstanding balance = $1000 - $824.74
= $175.26
Answer:
the dimensions that minimize the cost of the cylinder are R= 3.85 cm and L=12.88 cm
Step-by-step explanation:
since the volume of a cylinder is
V= π*R²*L → L =V/ (π*R²)
the cost function is
Cost = cost of side material * side area + cost of top and bottom material * top and bottom area
C = a* 2*π*R*L + b* 2*π*R²
replacing the value of L
C = a* 2*π*R* V/ (π*R²) + b* 2*π*R² = a* 2*V/R + b* 2*π*R²
then the optimal radius for minimum cost can be found when the derivative of the cost with respect to the radius equals 0 , then
dC/dR = -2*a*V/R² + 4*π*b*R = 0
4*π*b*R = 2*a*V/R²
R³ = a*V/(2*π*b)
R= ∛( a*V/(2*π*b))
replacing values
R= ∛( a*V/(2*π*b)) = ∛(0.03$/cm² * 600 cm³ /(2*π* 0.05$/cm²) )= 3.85 cm
then
L =V/ (π*R²) = 600 cm³/(π*(3.85 cm)²) = 12.88 cm
therefore the dimensions that minimize the cost of the cylinder are R= 3.85 cm and L=12.88 cm
