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Genrish500 [490]
3 years ago
12

WILL MARK BRAINLIEST

Mathematics
1 answer:
boyakko [2]3 years ago
6 0

Answer:

708.008

Step-by-step explanation:

hope i helps

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Scores on an aptitude test are distributed with a mean of 220 and a standard deviation of 30. The shape of the distribution is u
Evgen [1.6K]

Answer:

P(215<X<225) = 0.7620

Step-by-step explanation:

The shape of the distribution is unknow, however, the shape of the sampling distributions of the sample mean is approximately normal due to the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 220, \sigma = 30,n = 50, s = \frac{30}{\sqrt{50}} = 4.2426

P(215<X<225)

This is the pvalue of Z when X = 225 subtracted by the pvalue of Z when X = 215. So

X = 225

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{225 - 220}{4.2426}

Z = 1.18

Z = 1.18 has a pvalue of 0.8810

X = 215

Z = \frac{X - \mu}{s}

Z = \frac{215 - 220}{4.2426}

Z = -1.18

Z = -1.18 has a pvalue of 0.1190

0.8810 - 0.1190 = 0.7620

P(215<X<225) = 0.7620

6 0
3 years ago
1. What is asked in the problem?
Scorpion4ik [409]

Answer:

See Explanation

Step-by-step explanation:

Given

See attachment

Solving (1): What is asked

The requirement of the question is to determine the difference between the amount of sugar used between yesterday and today

Solving (2): The given facts

Yesterday = \frac{9}{10}kg

Today = \frac{3}{5}kg

Solving (3): Operation to be used

We use subtraction operation

Solving (4): The mathematical sentence

D = Yesterday - Today

D = \frac{9}{10}kg - \frac{3}{5}kg

D represents the difference

Solving (5): The solution

D = \frac{9}{10}kg - \frac{3}{5}kg

Take LCM

D = \frac{9 - 6}{10}kg

D = \frac{3}{10}kg

5 0
3 years ago
Thomas lives more than 0.55 km and less than 0.75 km from his school.
pshichka [43]

0.60 km which I got from https://quizizz.com

7 0
3 years ago
Which of the following values of y is a solution to the equation y^3-5?
ANEK [815]
<span>y3 - 5 hope this help u </span>
8 0
3 years ago
Camden has an action figure collection of 380 action figures. He keeps 55% of the action figures on his wall. How many action fi
svet-max [94.6K]
209 action figures on his wall

380/100 = 3.8
so there would be 3.8 action figures per 1%
then 3.8*55 =209
6 0
3 years ago
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