(6×5)×100=3,000 Since 6×5=30×100=3,000
john had 21.00After buying 2 notebooks he had 13.00
21-13= 8 / 2 =4 each notebook cost 4 dollars.
A = ( 15 , 15 )
B = ( 6 , 33 )
Thanks for watching buddy good luck.
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<span>By plotting, <em>(please see the image attached)</em> we can clearly see that neither side
is equal nor perpendicular to each other. Same condition of we use the distance
formula to compare the sides. The type of quadrilateral that has meets the
condition is a trapezoid</span>
You can use the Law of Cosines, if only one of which is missing: three sides and one angle. Hence, if the known properties of the triangle is SSS(side-side-side) or SAS (side-angle-side), this law is applicable.
You can use the Law of Sines if you want to equate the ratio of the sine of an angle and its opposite side. This can be used if the known properties of the triangle is ASA(angle-side-angle) or SAS.
The ambiguous case is the SAS triangle. This could be easily solved using Law of Sines than Law of Cosines. Take for example: side a = 4, side b = 10, angle A = 23°. Then, we can determine angle B through Sine Law.
sin 23°/4 = sin B/10
B = 77.64°
