A mass hanging from a pendulum at the end of a string of negligible mass. The string has a length of 0.84 m. With the string han
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a) 4.8 m/s² his average acceleration during the first 2.5 s
b) 15 m distance he cover during the first 2.5 seconds.
c) 31 m/s his speed as he finished the race.
<h3>(a) How to calculate the Average Acceleration ?</h3>Average acceleration is calculated by using Newtons first law of motion
v = u + at
where
u is initial velocity
v is final velocity
a is constant acceleration
t is time
Given u = 0m/s , v = 12 m/s and t = 2.5 sec
Therefore average acceleration is given by
a = 4.8 m/sec²
b) Here we will use newtons second law of motion
On substituting value we get
s = 15m
c) Here we will use newtons third law of motion
v² = u² + 2as
Here u = 0 , a = 4.8 m/s² and s = 100 m
Therefore
v² = 960
v = 31 m/s
Disclaimer: the question was given incomplete in the portal. Here is the complete question.
Question: Usain Bolt's 100m sprint Runner set the world record for the100 meter sprint during the 2009World Championships in Berlin with a time of 9.58 s, reaching a top speed of 12 m/s in about 2.5 s.
a. What was his average acceleration during the first 2.5 s?
b. What distance did he cover during the first 2.5 seconds, assuming his acceleration was constant?
c. If he were able to maintain this constant rate of acceleration, what would have been his speed as he finished the race?
Learn more about Newtons law of motion here:
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Answer: the image distance is -18, 28 cm this means behind of the concave mirror. The image size is 2.2 higher that the original so it has 8.8 cm with the same orientation as original and it is a virtual imagen.
Explanation: In order to sove the imagen formation for a concave mirror we have to use the following equation:
1/p+1/q=1/f where p and q represents the distance to the mirror for the object and imagen, respectively. f is the focal length for the concave mirror.
replacing the values we obtain:
1/8.3+1/q=1/15.2
so 1/q=(1/15.2)-(1/8.3)=-54.7*10^-3
then q=-18.28 cm
The magnification is given by M=-q/p=-(-18,28)/8.3= 2.2
We also add a picture to see the imagen formation for this case.
