Answer:
Any [a,b] that does NOT include the x-value 3 in it.
Either an [a,b] entirely to the left of 3, or
an [a,b] entirely to the right of 3
Step-by-step explanation:
The intermediate value theorem requires for the function for which the intermediate value is calculated, to be continuous in a closed interval [a,b]. Therefore, for the graph of the function shown in your problem, the intermediate value theorem will apply as long as the interval [a,b] does NOT contain "3", which is the x-value where the function shows a discontinuity.
Then any [a,b] entirely to the left of 3 (that is any [a,b] where b < 3; or on the other hand any [a,b] completely to the right of 3 (that is any [a,b} where a > 3, will be fine for the intermediate value theorem to apply.
Answer:
(x,y) = (-1,1)
Step-by-step explanation:
Given the equations
y = 2x + 3
x - y = -2
substitute the value of y in the first equation into the second
x - (2x + 3) = -2
x -2x - 3 = -2
-x - 3 = -2
add 3 to both sides
-x = -2 + 3
- x = 1
Divide both sides by -1
x = -1
Substitute into the first equation
y = 2(-1) + 3
y = -2 + 3
y = 1
The answer is c i’m pretty sure
Answer:
?=1O or 15
Step-by-step explanation:
Answer:
.5299192646
Step-by-step explanation:
Just plug it in a calculator
