Can someone help me find the roots of 3x^2+36x+81=0
2 answers:
Answer:
-3 and -9 are the roots.
Step-by-step explanation:
Answer:
x = -9, -3
Step-by-step explanation:
Step 1: Write equation
3x² + 36x + 81 = 0
Step 2: Solve for <em>x</em>
- Factor out 3: 3(x² + 12x + 27) = 0
- Factor quadratic: 3(x + 3)(x + 9) = 0
- Divide both sides by 3: (x + 3)(x + 9) = 0
- Solve individual roots: x = -9, -3
Step 3: Check
<em>Plug in x to verify it's a solution.</em>
3(-9)² + 36(-9) + 81 = 0
3(81) - 324 + 81 = 0
243 - 243 = 0
0 = 0
3(-3)² + 36(-3) + 81 = 0
3(9) - 108 + 81 = 0
27 - 27 = 0
0 = 0
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Answer:
(6,-7)
Step-by-step explanation:
subtract them:
-8x - 5y = -13
-4x - 5y = 11
you get
-4x = -24
so x = 6
plug x into the second equation:
-24 - 5y = 11
-5y = 35
y = -7
so your solution is (6,-7).
Answer:
Step-by-step explanation:
Its (1,3) and (-3, -2)
Yes
7x6=42
8x6=48
Hope that helped :D
Answer:
D) 2x<u>2</u>
Step-by-step explanation:
i got i right on the test
1288/(4x7)
=1288/28
=46 sandwiches