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alisha [4.7K]
3 years ago
6

Using the table, give the percentage associated with each unit of standard deviation in the standard normal curve to the

Mathematics
1 answer:
Furkat [3]3 years ago
4 0

Answer:

Using the table, give the percentage associated with each unit of standard deviation in the standard normal curve to the

nearest hundredth.

х

Area, A(x) x

Area, A(x)

0.2

0.4

0.6

0.8

1.0

1.2

1.4

1.6

1.8

2.0

0.0793

0.1554

0.2257

0.2881

0.3413

0.3849

0.4192

0.4452

0.4641

0.4772

2.2

2.4

2.6

2.8

3.0

3.2

3.4

3.6

3.8

4.0

0.4861

0.4918

0.4953

0.4974

0.4987

0.4993

0.4997

0.4998

0.4999

0.5000

Standard Deviation Percentage Area

-1 to 0

81.85 %

O to +1

34.13 %

Step-by-step explanation:

Using the table, give the percentage associated with each unit of standard deviation in the standard normal curve to the

nearest hundredth.

х

Area, A(x) x

Area, A(x)

0.2

0.4

0.6

0.8

1.0

1.2

1.4

1.6

1.8

2.0

0.0793

0.1554

0.2257

0.2881

0.3413

0.3849

0.4192

0.4452

0.4641

0.4772

2.2

2.4

2.6

2.8

3.0

3.2

3.4

3.6

3.8

4.0

0.4861

0.4918

0.4953

0.4974

0.4987

0.4993

0.4997

0.4998

0.4999

0.5000

Standard Deviation Percentage Area

-1 to 0

81.85 %

O to +1

34.13 %

Using the table, give the percentage associated with each unit of standard deviation in the standard normal curve to the

nearest hundredth.

х

Area, A(x) x

Area, A(x)

0.2

0.4

0.6

0.8

1.0

1.2

1.4

1.6

1.8

2.0

0.0793

0.1554

0.2257

0.2881

0.3413

0.3849

0.4192

0.4452

0.4641

0.4772

2.2

2.4

2.6

2.8

3.0

3.2

3.4

3.6

3.8

4.0

0.4861

0.4918

0.4953

0.4974

0.4987

0.4993

0.4997

0.4998

0.4999

0.5000

Standard Deviation Percentage Area

-1 to 0

81.85 %

O to +1

34.13 %

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Answer:

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Step-by-step explanation:

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Answer:

8 or 32

Step-by-step explanation:

So we are given two coordinates and the length of the segment formed by those coordinates.

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The distance formula is given by the formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Substitute (-2,n) for x₁ and y₁ and (-7,20) for x₂ and y₂. Also, since we already know that the length is 13, substitute it for d. Thus:

(13)=\sqrt{((-7)-(-2))^2+((20)-(n))^2}

Do the operations within the parentheses:

13=\sqrt{(-7+2)^2+(20-n)^2}\\13=\sqrt{(-5)^2+(20-n)^2}

Now, square both sides to take out the square root:

(13)^2=(\sqrt{(-5)^2+(20-n)^2})^2

Simplify:

169=(-5)^2+(20-n)^2

Square (-5):

169=25+(20-n)^2

Subtract 25 from both sides. The right cancels:

(169)-25=(25+(20-n)^2)-25\\144=(20-n)^2

Now, take the square root of both sides.

\pm\sqrt{144}=\sqrt{(20-n)^2}

Simplify:

\pm12=(20-n)

So, we have two solutions:

(12=20-n)\text { or }(-12=20-n)

On the left, subtract 20. On the right, also subtract 20:

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Divide both sides by -1:

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Describe the key aspects of the function f(x) = –x2 – 2x – 1.
amid [387]

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sweet-ann [11.9K]
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There is a 60 minute gap between the two clocks.

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if we are going 2 mins back and 1 min in

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since each 3 represent an hour,

to get 60 min gap>60/3=20 hours

Take clock 1 for example, which read 12:00, in reality the time is (12:00-20 minutes)=11:40

or

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