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3 years ago

Rathan thinks all factors of even numbers are even. Which explains whether Rathan is correct?

2 answers:

7 0

In order to prove Rathan wrong, we only need one counterexample. Take the number 6. 6 is even, but it has the odd number 3 as a factor, so clearly, not all factors of even numbers are even.

Dominik [7]3 years ago

3 0

Answer: Rathan is incorrect.

Step-by-step explanation:

For a number X, the factors of the numer are other numbers that we multiplicate togheter to get the number X.

for example if X = 16, the factors of 16 can be:

2*8 = 16

4*4 = 16

etc.

Now, let's take some even numbers like 6 and 24.

Now, those two numbers have a factor in common.

3*2 = 6

3*8 = 24

both numbers have the same factor, 3, wich is an odd number. So we have found an example that says that Rathan is incorrect.

You might be interested in

Write the ratio as a fraction in simplest form with whole numbers in the numerator and denominator 16 cm to 20 cm

emmainna [20.7K]

Answer:

4/5

Step-by-step explanation:

16/20 in a simpler form is 8/10. 8/10 in the simplest form is 4/5 (division)

8 0

3 years ago

Read 2 more answers

If <img src="https://tex.z-dn.net/?f=%20300cm%5E%7B2%7D%20" id="TexFormula1" title=" 300cm^{2} " alt=" 300cm^{2} " align="absmid

Artist 52 [7]

Check the picture below. Recall, is an open-top box, so, the top is not part of the surface area, of the 300 cm². Also, recall, the base is a square, thus, length = width = x.

$\bf \textit{volume of a rectangular prism}\\\\
V=lwh\quad 
\begin{cases}
l = length\\
w=width\\
h=height\\
-----\\
w=l=x
\end{cases}\implies V=xxh\implies \boxed{V=x^2h}\\\\
-------------------------------\\\\
\textit{surface area}\\\\
S=4xh+x^2\implies 300=4xh+x^2\implies \cfrac{300-x^2}{4x}=h
\\\\\\
\boxed{\cfrac{75}{x}-\cfrac{x}{4}=h}\\\\
-------------------------------\\\\
V=x^2\left( \cfrac{75}{x}-\cfrac{x}{4} \right)\implies V(x)=75x-\cfrac{1}{4}x^3$

so.. that'd be the V(x) for such box, now, where is the maximum point at?

$\bf V(x)=75x-\cfrac{1}{4}x^3\implies \cfrac{dV}{dx}=75-\cfrac{3}{4}x^2\implies 0=75-\cfrac{3}{4}x^2
\\\\\\
\cfrac{3}{4}x^2=75\implies 3x^2=300\implies x^2=\cfrac{300}{3}\implies x^2=100
\\\\\\
x=\pm10\impliedby \textit{is a length unit, so we can dismiss -10}\qquad \boxed{x=10}$

now, let's check if it's a maximum point at 10, by doing a first-derivative test on it. Check the second picture below.

so, the volume will then be at $\bf V(10)=75(10)-\cfrac{1}{4}(10)^3\implies V(10)=500 \ cm^3$

6 0

3 years ago

Three of the following steps are used in writing a mixed number as an improper fraction. Which step does NOT belong?

QveST [7]

I don't see the steps, but the steps that I use are:
1. Multiply the denominator by the whole number
2. Then you add the numerator to your sum.
3. The number that you just got by doing those steps is now going to be your numerator and your old denominator is going to stay your denominator.

Example:

2 2/3
3*2=6
6+2=8
8/3 is your new answer.

3 0

3 years ago

Help me pls look at this PHTOo Bc I don’t know how to explain

Ray Of Light [21]

Answer:

42.1

Step-by-step explanation:

15.2% = 0.152

277 * 0.152 = 42.104

42.1 megabytes have been downloaded.

Hope this is helpful.

4 0

2 years ago

Read 2 more answers

A snail can crawl at a rate of 6 cm in 0.75 minutes. Which representation shows the distance a snail can travel at this rate?

Bogdan [553]

Answer: 0.00133m/s

Step-by-step explanation:

Given

distance crawled by the snail = 6cm = 0.06m

Time taken = 0.75minutes = 0.75*60

Time taken = 45secs

Required

constant rate of change of the snail's crawl (speed)

Speed of the snail = distance/time;

Speed of the snail = 0.06/45

Speed of the snail = 0.00133m/s

Hence the constant rate of change of the snail's crawl in m/s is 0.00133m/s

7 0

2 years ago