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oee [108]
3 years ago
10

Rathan thinks all factors of even numbers are even. Which explains whether Rathan is correct?

Mathematics
2 answers:
Nesterboy [21]3 years ago
7 0
In order to prove Rathan wrong, we only need one counterexample. Take the number 6. 6 is even, but it has the odd number 3 as a factor, so clearly, not all factors of even numbers are even.
Dominik [7]3 years ago
3 0

Answer: Rathan is incorrect.

Step-by-step explanation:

For a number X, the factors of the numer are other numbers that we multiplicate togheter to get the number X.

for example if X = 16, the factors of 16 can be:

2*8 = 16

4*4 = 16

etc.

Now, let's take some even numbers like 6 and 24.

Now, those two numbers have a factor in common.

3*2 = 6

3*8 = 24

both numbers have the same factor, 3, wich is an odd number. So we have found an example that says that Rathan is incorrect.

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Write the ratio as a fraction in simplest form with whole numbers in the numerator and denominator 16 cm to 20 cm
emmainna [20.7K]

Answer:

4/5

Step-by-step explanation:

16/20 in a simpler form is 8/10. 8/10 in the simplest form is 4/5 (division)

8 0
3 years ago
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Artist 52 [7]
Check the picture below.  Recall, is an open-top box, so, the top is not part of the surface area, of the 300 cm².  Also, recall, the base is a square, thus, length = width = x.

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so.. that'd be the V(x) for such box, now, where is the maximum point at?

\bf V(x)=75x-\cfrac{1}{4}x^3\implies \cfrac{dV}{dx}=75-\cfrac{3}{4}x^2\implies 0=75-\cfrac{3}{4}x^2&#10;\\\\\\&#10;\cfrac{3}{4}x^2=75\implies 3x^2=300\implies x^2=\cfrac{300}{3}\implies x^2=100&#10;\\\\\\&#10;x=\pm10\impliedby \textit{is a length unit, so we can dismiss -10}\qquad \boxed{x=10}

now, let's check if it's a maximum point at 10, by doing a first-derivative test on it.  Check the second picture below.

so, the volume will then be at   \bf V(10)=75(10)-\cfrac{1}{4}(10)^3\implies V(10)=500 \ cm^3

6 0
3 years ago
Three of the following steps are used in writing a mixed number as an improper fraction. Which step does NOT belong?
QveST [7]
I don't see the steps, but the steps that I use are:
1. Multiply the denominator by the whole number 
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Example:

2 2/3 
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3 years ago
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42.1

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4 0
2 years ago
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Speed of the snail = 0.00133m/s

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7 0
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