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oee [108]
3 years ago
10

Rathan thinks all factors of even numbers are even. Which explains whether Rathan is correct?

Mathematics
2 answers:
Nesterboy [21]3 years ago
7 0
In order to prove Rathan wrong, we only need one counterexample. Take the number 6. 6 is even, but it has the odd number 3 as a factor, so clearly, not all factors of even numbers are even.
Dominik [7]3 years ago
3 0

Answer: Rathan is incorrect.

Step-by-step explanation:

For a number X, the factors of the numer are other numbers that we multiplicate togheter to get the number X.

for example if X = 16, the factors of 16 can be:

2*8 = 16

4*4 = 16

etc.

Now, let's take some even numbers like 6 and 24.

Now, those two numbers have a factor in common.

3*2 = 6

3*8 = 24

both numbers have the same factor, 3, wich is an odd number. So we have found an example that says that Rathan is incorrect.

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Glad I could help, and good luck!


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