Answer:
a.) 490m
b.) 98m/s
Explanation:
Given that the
Acceleration g = 9.8 m/s^2
Time = 10s
Since the parachutist jumps out of an aeroplane. The parachutist jumped out from rest. Initial velocity U is therefore equal to zero. That is,
U = 0
Distance covered = height H
The height can be calculated by using second equation of motion
H = Ut + 1/2gt^2
Substitute g and t into the formula
H = 1/2 × 9.8 × 10^2
H = 490 m
Therefore, she travels as far as 490 m
b.) Her final velocity can be calculated by using third equation of motion
V^2 = U^2 + 2gH
Substitute g and H into the formula.
Remember that U = 0
V^2 = 2 × 9.8 × 490
V^2 = 9604
V = sqrt (9604)
V = 98 m/s
Therefore, her final velocity is 98 m/s
Momentum is a product of mass and the velocity of a body. The initial momentum is always equal to the final momentum during collisions between two bodies.
Therefore; M1U1 +M2U2 = M1V1+ M2V2, where m1 is the mass of tracey and m2 is the mass of jonas, while u is the initial velocity and v is the final velocity.
(32 ×0)+ (45×0) = (32 × v1) + (45 × 0.50)
0 = 32V1 + 22.5
32 V1 = -22.5
V1 = - 0.703 ( negative indicates difference in direction)
There, Tracey's speed will be 0.703 m/s
The one that's completely submerged is displacing more water, so the buoyant force on it is greater.
Answer:
Tension= 21,900N
Components of Normal force
Fnx= 17900N
Fny= 22700N
FN= 28900N
Explanation:
Tension in the cable is calculated by:
Etorque= -FBcostheta(1/2L)+FT(3/4L)-FWcostheta(L)= I&=0 static equilibrium
FTorque(3/4L)= FBcostheta(1/2L)+ FWcostheta(L)
Ftorque=(Fcostheta(1/2L)+FWcosL)/(3/4L)
Ftorque= 2/3FBcostheta+ 4/3FWcostheta
Ftorque=2/3(1350)(9.81)cos55° + 2/3(2250)(9.81)cos 55°
Ftorque= 21900N
b) components of Normal force
Efx=FNx-FTcos(90-theta)=0 static equilibrium
Fnx=21900cos(90-55)=17900N
Fy=FNy+ FTsin(90-theta)-FB-FW=0
FNy= -FTsin(90-55)+FB+FW
FNy= -21900sin(35)+(1350+2250)×9.81=22700N
The Normal force
FN=sqrt(17900^2+22700^2)
FN= 28.900N
Answer:
Bill's motor power: W_B = F x S / T = F x 0.35 / 2= 0.175F
Nageen's motor power: W_N = F x S / T = F x 0.35 / 1.8 = 0.194F
=> 0.194F > 0.175F => Nageen's motor applied more power to the box than Bill's motor.
