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2 years ago

The moon does not stay at the same distance from the earth.why?

Physics

1 answer:

Artist 52 [7]2 years ago

5 0

Answer:

The moon does not stay at the same distance of the earth because the ortbit of the moon is slightly elliptical. If earth is not tilted at an angle of 66.5°, there will be no change in the season and the earth will have equal length of days and night.

Explanation:

mark me brainlest

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A person holds a portable fire extinguisher that ejects 1.0kg of water per second horizontally at a speed of 6.0 m/s. What newto

Leviafan [203]

Answer:

6 N

Explanation:

$\dfrac{m}{t}$ = Mass flow rate = 1 kg/s

v = Final velocity = 6 m/s

u = Initial velocity = 0 m/s

Force is obtained when we divide change in momentum by time

$F=\dfrac{m(v-u)}{t}\\\Rightarrow F=\dfrac{m}{t}(v-u)\\\Rightarrow F=1(6-0)\\\Rightarrow F=6\ N$

The force the person exert on the extinguisher in order to prevent it from accelerating is 6 N

7 0

3 years ago

Americium-241 is used in smoke detectors. It undergoes alpha decay with a half life of 432 years. The alpha particles ionize som

babymother [125]

Answer:

860.6 years.

Explanation:

The parameters given are;

Initial detector activity = 370000 alpha decays per second

Final detector activity = 93000 alpha decays per second

Formula for time to change in activity is given by the following relation;

$t_{93000} = \dfrac{-ln\dfrac{A}{A_0} }{\lambda} = \dfrac{-ln\dfrac{93000}{370000} }{5.08 \times 10^{-11}} = 2.72 \times 10^{10} \, seconds$

t₉₃₀₀₀ = 2.72 × 10¹⁰ seconds = 860.6 years.

3 0

3 years ago

At what angle should the axes of two Polaroids be placed so as to reduce the intensity of the incident unpolarized light to 1515

Talja [164]

Complete Question

At what angle should the axes of two Polaroids be placed so as to reduce the intensity of the incident unpolarized light to 1/5.

Answer:

The angle is

Explanation:

From the question we are told that

The light emerging from second Polaroid is 1/5 the unpolarized

Generally the intensity of light emerging from the first Polaroid is mathematically represented as

$I_1 = \frac{I_o}{ 2 }$

Generally from the Malus law the intensity of light emerging from the second Polaroid is mathematically represented

$I_2 = I_1 cos^2 (\theta )$

=> $cos^2 (\theta ) = \frac{I_2}{I_1 }$

=> $cos (\theta) = \sqrt{ \frac{I_2}{I_1} }$

From the question $I_2 = \frac{I_o}{5}$

$cos (\theta) = \sqrt{ \frac{ \frac{ I_o}{5} }{\frac{I_o}{2} } }$

$cos (\theta) = \sqrt{ \frac{2}{5} }$

=> $\theta = cos ^{-1} [\sqrt{\frac{2}{5}} ]$

=> $\theta = 50.77^o$

8 0

3 years ago

PLS HELP ME!

jeyben [28]

Answer:

$\underline{ \boxed{ yes}}\\$

Explanation:

$given : initial \: velocity \: (u )= 40 {ms}^{ - 1} \\ given : final \: velocity \: (u )= 0 {ms}^{ - 1} \\ given : - (acceleration) \: (a_r) = 2 {ms}^{ - 2} \\ given : distance \: (s) \: = \: ? : \\ but \: {v}^{2} = {u}^{2} + 2( a)s\\ {0}^{2} = {40}^{2} + 2( - 2)s \\ - {40}^{2} = - 4s \\ s = \frac{ - {40}^{2} }{ - 4} \\ s = \frac{1600}{4} \\s = 400 \: m$

3 0

2 years ago

3) El motor de una moto le imprime una velocidad de 90 km/h al aplicar sobre ella una fuerza de 240 N. ¿Cuál es la potencia de l

Alisiya [41]

Answer:

P = 6000 W

Explanation:

The given question is "The motor of a motorcycle gives it a speed of 90 km / h when a force of 240 N is applied to it. What is the power of the motorcycle in watts?"

Given that,

Speed of a motorcycle, v = 90 km/h = 25 m/s

Force applied to the motorcycle, F = 240 N

We need to find the power of the motorcycle. We know that,

Power = Fv

So,

P = 240 N × 25 m/s

= 6000 W

So, the required power of the motorcycle is equal to 6000 W.

5 0

2 years ago

The moon does not stay at the same distance from the earth.why?​

The moon does not stay at the same distance from the earth.why?