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geniusboy [140]
1 year ago
9

Which of the following would be the magnitude of the vector given a horizontal component of 30 and a

Physics
1 answer:
Scorpion4ik [409]1 year ago
7 0

Answer:

50

Explanation:

Use the Pythagorean theorem to find the length of the diagonal, or the hypotenuse of an imaginary triangle. 30^2 + 40^2 = 2500, which is 50^2. So, the magnitude is 50.

Brainliest, please :)

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Which is usually greater for a pair of surfaces, the coefficient of static friction or the coefficient of sliding friction? why
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Explanation :

Static friction is the frictional force between two objects that are at rest. While sliding friction is the frictional force between two objects in contact and are sliding w.r.t each other.

Static friction is usually greater than sliding friction because in static friction the contact forces is more and the interlocking between objects is tight as compared to sliding friction.    

5 0
3 years ago
The LIGHT/DARKcontrol of an automatic toaster is placed at a particular setting. The toast at this setting will always be the sa
hichkok12 [17]
The toast at this setting will always be the same color because the toaster uses a compensating thermostat. Depending on the setting, the compensating thermostat will be used to regulate the heat settings at different amounts of time. In one setting, the compensating thermostat could go on for much longer than the other setting before shutting off.
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Is it possible for a population with a high birth rate to decrease in size.
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7 0
3 years ago
Find the solution set of x + y = 5, 2 x - y = 7
STALIN [3.7K]
X + y = 5
x = 5 - y

2x - y = 7
2(5-y) - y = 7
10 - 2y - y = 7
10 - 3y = 7
10 - 7 = 3y
3 = 3y
y = 1

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4 0
3 years ago
Runner A is initially 6.0 km west of a flagpole and is running with a constant velocity of 9.0 km/h due east. Runner B is initia
sergejj [24]

Answer:

0.176m from the flagpole, westward.

Explanation:

Let the Eastward be the positive direction. So initially runner A is at position -6km, running with velocity of 9km/h while runner B is at position 5km running at a velocity of -8km/h. We can conduct the following equation for their distances over the same time t

s_A = -6 + 9t

s_B = 5 - 8t

When A an B meets, they are at the same position and at the same time. So

s_A = s_B

-6 +9t = 5 - 8t

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s_A = -6 + 9*0.647 = -0.176 m

So where they meet is 0.176m from the flagpole, westward.

5 0
3 years ago
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