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geniusboy [140]
2 years ago
9

Which of the following would be the magnitude of the vector given a horizontal component of 30 and a

Physics
1 answer:
Scorpion4ik [409]2 years ago
7 0

Answer:

50

Explanation:

Use the Pythagorean theorem to find the length of the diagonal, or the hypotenuse of an imaginary triangle. 30^2 + 40^2 = 2500, which is 50^2. So, the magnitude is 50.

Brainliest, please :)

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Which example identifies a change in motion that produces acceleration?
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Acceleration is the rate at which an object changes its velocity. It defines how much the velocity is changing. The acceleration can be negative and positive. Negative acceleration is when the object slows down, while positive while the object goes faster.
<span>A ball moving at a constant speed around a circular track produces acceleration. </span>
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Which of the following means "free from all organisms''?
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Answer:

4. Sterilization

Explanation:

A reservoir refers to the breeding ground or natural habitat of micro living organisms such as bacterias, fungi, worms, etc. Thus, a reservoir hosts or harbours pathogens and usually serves as a source of infection to other living organisms.

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3 0
3 years ago
If the velocity of a car is 45 km/h west how far can it travel in 0.5 hours?
marissa [1.9K]

Answer: 22.5 km

Explanation: Solution:

v=d/t

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6 0
3 years ago
A fighter plane flying at constant speed 420 m/s and constant altitude 3300 m makes a turn of curvature radius 11000 m. On the g
Arada [10]

Answer:

"Apparent weight during the "plan's turn" is  519.4 N

Explanation:

The "plane’s altitude" is not so important, but the fact that it is constant tells us that the plane moves in a "horizontal plane" and its "normal acceleration" is \mathrm{a}_{\mathrm{n}}=\frac{v^{2}}{R}

Given that,

v = 420 m/s

R = 11000 m

Substitute the values in the above equation,

a_{n}=\frac{420^{2}}{11000}

a_{n}=\frac{176400}{11000}

a_{n}=16.03 \mathrm{m} / \mathrm{s}^{2}

It has a horizontal direction. Furthermore, constant speed implies zero tangential acceleration, hence vector a = vector a N. The "apparent weight" of the pilot adds his "true weight" "m" "vector" "g" and the "inertial force""-m" vector a due to plane’s acceleration, vectorW_{\mathrm{app}}=m(\text { vector } g \text { -vector a })

In magnitude,

| \text { vector } g-\text { vector } a |=\sqrt{\left(g^{2}+a^{2}\right)}

| \text { vector } \mathrm{g}-\text { vector } \mathrm{a} |=\sqrt{\left(9.8^{2}+16.03^{2}\right)}

| \text { vector } \mathrm{g}-\text { vector } \mathrm{a} |=\sqrt{(96.04+256.96)}

| \text { vector } \mathrm{g}-\text { vector } \mathrm{a} |=\sqrt{353}

| \text { vector } \mathrm{g}-\text { vector } \mathrm{a} |=18.78 \mathrm{m} / \mathrm{s}^{2}

Because vector “a” is horizontal while vector g is vertical. Consequently, the pilot’s apparent weight is vector

\mathrm{W}_{\mathrm{app}}=(18.78 \mathrm{m} / \mathrm{s}^ 2)(53 \mathrm{kg})=995.77 \mathrm{N}

Which is quite heavier than his/her true weigh of 519.4 N

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3 years ago
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