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2 years ago

Why was nuclear energy first developed?

Physics

1 answer:

Helga [31]2 years ago

7 0

Nuclear energy was not developed. It has existed for as long as time has existed, that is, since the big bang.

The thing that was developed was humans' ability to USE nuclear energy, to do what we want it to do, when we want it to do it.

The reason this was first developed was to bomb the holy beans out of Japan, in order to win World War II.

Today (2020), nine of the world's nations are known to have 14,285 nuclear bombs in storage, for the same general purpose. Seven of these nations are storing 1,170 of these bombs (about 8 percent), and the USA and Russia have all the rest ... 13,035 nuclear bombs.

All nine of these nations promise that they have no plan to use their bombs, they don't want to use them, it would be wrong and terrible to use them, and they will never be the first to use them, but they need to modernize their bombs so that theirs are better than anybody else's bombs, and they need to keep their bombs for as long as anybody else has any, and then maybe a little longer, just in case.

In the years after the ability to bomb the holy beans out of other people was developed, and enough equipment was built to do it 14 thousand times, the ability to use nuclear energy for other purposes was also developed. It's used now to generate electrical energy, and to do several jobs in Medical science.

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As a new electrical technician, you are designing a large solenoid to produce a uniform 0.170 T magnetic field near the center o

MrRa [10]

Answer:

18.6012339739 A

Explanation:

$\mu_0$ = Vacuum permeability = $4\pi \times 10^{-7}\ H/m$

L = Length of wire = 55 cm

N = Number of turns = 4000

I = Current

Magnetic field is given by

$B=\dfrac{\mu_0NI}{L}\\\Rightarrow I=\dfrac{BL}{\mu_0N}\\\Rightarrow I=\dfrac{0.17\times 0.55}{4\pi \times 10^{-7}\times 4000}\\\Rightarrow I=18.6012339739\ A$

The current necessary to produce this field is 18.6012339739 A

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3 years ago

gAn optical engineer needs to ensure that the bright fringes from a double-slit are 15.7 mm apart on a detector that is from the

igomit [66]

Answer:

d = 68.5 x 10⁻⁶ m = 68.5 μm

Explanation:

The complete question is as follows:

An optical engineer needs to ensure that the bright fringes from a double-slit are 15.7 mm apart on a detector that is 1.70m from the slits. If the slits are illuminated with coherent light of wavelength 633 nm, how far apart should the slits be?

The answer can be given by using the formula derived from Young's Double Slit Experiment:

$y = \frac{\lambda L}{d}\\\\d =\frac{\lambda L}{y}\\\\$

where,

d = slit separation = ?

λ = wavelength = 633 nm = 6.33 x 10⁻⁷ m

L = distance from screen (detector) = 1.7 m

y = distance between bright fringes = 15.7 mm = 0.0157 m

Therefore,

$d = \frac{(6.33\ x\ 10^{-7}\ m)(1.7\ m)}{0.0157\ m}\\\\$

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3 years ago

What are loops of gas on sun that link different parts of sunspot regions together?

love history [14]

So we want to know what are loops of gas on the Sun that link different parts of sunspot regions together. A large and bright gaseous feature that extends from the surface of the Sun that links different parts of sunspot regions together is called Prominence. They are on the Suns surface in the photosphere and they extend outwards into the Corona.

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2 years ago

Which of the following statements about Gaussʹs law are correct? (There may be more than one correct choice.) Question 3 options

irina1246 [14]

Answer:

If a Gaussian surface is completely inside an electrostatic conductor, the electric field must always be zero at all points on that surface.

Explanation:

Option A is incorrect because, given this case, it is easier to calculate the field.

Option B is incorrect because, in a situation where the surface is placed inside a uniform field, option B is violated

Option C is also incorrect because it is possible to be a field from outside charges, but there will be an absence of net flux through the surface from these.

Hence, option D is the correct answer. "If a Gaussian surface is completely inside an electrostatic conductor, the electric field must always be zero at all points on that surface."

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2 years ago

An observer that moves with an electrical charge senses:

Shtirlitz [24]

Here observer is moving along with an electrical charge

now magnetic field on a moving charge is given by equation

$F = qvB sin\theta$