The amplitude of a wave<span> refers to the maximum amount of displacement of a particle on the medium from its rest position. ... So in the end, the </span>amplitude<span> of a transverse pulse is related to the energy which that pulse transports through the medium.</span>
Answer:
Ffriction = 90 N
coefficient = 0.3
Explanation:
First, note that the sum of all the forces in the x directions equals the mass multiplied by the acceleration in the x direction.
assuming the direction of the pulling force is positive,
243 N - Ffriction = m * a
m= 30.6 kg
a= 5 m/s/s
Ffriction= 243 - m*a
Ffriction= 243 - (30.6)(5)
Ffriction=90 N
The force of friction is equal to the coefficient of friction multiplied by the normal force on the object. Because the pulling force is completely horizontal, the normal force of the object is equal to its weight, which is m * g, or (30.6 kg)(9.8 m/s/s) = 299.88 N
Ffriction = coefficient * Fnormal
90 = coefficient * 299.88
coefficient = 0.3
Answer:75 percent
Explanation:so in order tro fin d thge efficiency i used the forumla ,efficency=useful output energy/input energyx100%,in order to use this formula i needed the output,which i found by subtracting the input energy with wasted energy,that gave me the output,and after founding the output,i put that into the formula,
output energy=input energy - wasted energy
output energy=6000j-1500j
output energy=4500
put that into the formula
efficiency =output energy/input enrgy x100%
efficiency=4500/6000 multiplied by 100%
efficiency=0.75x100%
efficiency=75%
1). The "Opera" at 90.5 MHz has lower frequency,
so its wavelength is longer.
2). Whichever station is transmitting with higher power
has waves with higher energy.
Each photon of the transmission at 107.1 MHz carries more energy,
because the energy of a photon is proportional to its frequency.
But it's a mistake to think that the station at higher frequency has
waves with higher energy.
