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aalyn [17]
3 years ago
9

Please help ill give brainliest​

Mathematics
1 answer:
Paul [167]3 years ago
3 0
1.c
2.d
3.b
4.a
Im sure about 1 and 4 but a little hesitant on 2 and 3 but good luck pretty sure it’s right
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400 Suppose a particular surveillance system has a 99% chance of correctly identifying a future terrorist and a 99.8% chance of
alexgriva [62]

Answer:

1.236 × 10^(-3)

Step-by-step explanation:

Let A be the event that the person is a future terrorist

Let B the event that the person is identified as a terrorist

We are told that there are 1,000 future terrorists in a population of 400 million. Thus, the Probability that the person is a terrorist is;

P(A) = 1000/400000000

P(A) = 0.0000025

P(A') = 1 - P(A)

P(A') = 1 - 0.0000025

P(A') = 0.9999975

We are told that the system has a 99% chance of correctly identifying a future terrorist. Thus; P(B|A) = 0.99

Thus, P(B'|A) = 1 - P(B|A)

P(B'|A) = 1 - 0.99

P(B'|A) = 0.01

We are told that there is a 99.8% chance of correctly identifying someone who is not a future terrorist. Thus; P(B'|A') = 0.998

Hence: P(B|A') = 1 - P(B'|A')

P(B|A') = 1 - 0.998

P(B|A') = 0.002

We want to find the probability that someone who is identified as a terrorist, is actually a future terrorist. This is represented by: P(A|B)

We can find it from bayes theorem as follows;

P(A|B) = [P(B|A) × P(A)]/[(P(B|A) × P(A)) + (P(B|A') × P(A')]

Plugging in the relevant values;

P(A|B) = [0.99 × 0.0000025]/[(0.99 × 0.0000025) + (0.002 × 0.9999975)]

P(A|B) = 0.00123597357 = 1.236 × 10^(-3)

8 0
3 years ago
Hellpppp D:<br><br> Solve for x in the triangle. Round your answer to the nearest tenth
SIZIF [17.4K]

Answer:

x = 12.6

Step-by-step explanation:

Can I have Brainliest please?

8 0
3 years ago
The length of a rectangle is x times the square root of 100. The width is one-half y more than three-halves x. Given that the ar
dimulka [17.4K]

Answer:

15x^2+5xy-125=0

Step-by-step explanation:

We are give the following in the question:

Dimensions of rectangle:

Length , l =

l = x\sqrt{100} = 10x

Width of rectangle, w =

w = \dfrac{y}{2} +\dfrac{3x}{2}

Area of rectangle = 125 square cm.

Area of rectangle =

A =l\times w

Putting values, we get,

125 = 10x\times (\dfrac{y}{2}+\dfrac{3x}{2})\\\\125 = 5xy+15x^2\\15x^2+5xy-125=0

is the required equation.

7 0
3 years ago
Read 2 more answers
Which expression is equivalent to
nirvana33 [79]

For this case, we must find an expression equivalent to:

\frac {-9x ^ {- 1} y ^ {- 9}} {- 15x ^ 5y ^ {- 3}}

By definition of power properties we have:

a ^ {- 1} = \frac {1} {a ^ 1} = \frac {1} {a}

Rewriting the previous expression we have:

The "-" are canceled and we take into account that:

\frac {9} {15} = \frac {3} {5}

So:

\frac {3} {5x^5 * x ^ 1 *y ^ 9* y ^ {- 3}} =

According to one of the properties of powers of the same base, we must put the same base and add the exponents:

\frac {3} {5x ^ {5 + 1} * y ^ {9-3}} =\\\frac {3} {5x ^ 6 * y ^ 6}

Answer:

\frac {3} {5x ^ 6 * y ^ 6}

Option B

3 0
3 years ago
Read 2 more answers
An online health and medicine company claims that about 50% of Internet users would go to an online sight first for
Serggg [28]

Answer:

The claim that less than 50% of internet users get their health questions answered online is correct, given that according to the survey, 45.98% of people do.

Step-by-step explanation:

Since an online health and medicine company claims that about 50% of Internet users would go to an online sight first for information regarding health and medicine, and a random sample of 1318 Internet users was asked where they will go for information the next time they need information about health or medicine; 606 said that they would use the Internet, to test the claim that less than 50% of Internet users get their health questions answered online, the following calculation must be performed:

1318 = 100

606 = X

606 x 100/1318 = X

60600/1318 = X

45.978 = X

Therefore, the claim that less than 50% of internet users get their health questions answered online is correct, given that according to the survey, 45.98% of people do.

6 0
3 years ago
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