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hichkok12 [17]
3 years ago
9

determine the percent yield for carbon dioxide if 4.50 moles of propane yielded 7.64 moles of carbon dioxide

Chemistry
1 answer:
ira [324]3 years ago
3 0

Answer:

Percent yield = 57%

Explanation:

Given data:

Number of moles of propane = 4.50 mol

Number of moles of carbon dioxide = 7.64 mol

Percent yield = ?

Solution:

Chemical equation:

C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

Now we will compare the moles of propane and carbon dioxide.

                            C₃H₈            :            CO₂

                                 1               ;                3

                                  4.50        :              3×4.50 = 13.5 mol

Percent yield:

Percent yield = actual yield / theoretical yield × 100

Percent yield =  7.64 mol / 13.5 mol × 100

Percent yield = 0.57× 100

Percent yield = 57%

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A flask containing 855 grams of water was heated. If the temperature of the water was raised from 21.0 to 85.0 degrees Celsius,
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Answer:

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Explanation:

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Q = c * m * ΔT

where Q is the heat exchanged by a body of mass m, constituted by a substance of specific heat c and where ΔT is the variation in temperature.

In this case:

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Replacing:

Q= 4.184 \frac{J}{g*C} *855 g* 64 C

Solving:

Q= 228,948.48 J

<u><em>The heat absorbed by the water is 228,948.48 J</em></u>

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