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2 years ago

In the diagram shown, what is occurring at the section marked 4 ?

Chemistry

1 answer:

cluponka [151]2 years ago

4 0

Answer:

Vaporization

Since the question does not specify what molecule is being acted upon by the increment in temperature, I'll assume it's water.

When first taken out of the fridge, water is in the form of ice, and it has not been affected by a change in temperature yet, so it's at the origin.

(origin = ice)

As you raise the temperature, however, the ice starts to melt, and melting occur during phase 2. You have to keep the temperature constant for the process to properly occur.

(phase 2 = melting)

After it finishes melting, the ice is now in it's liquid state, which is water. The temperature continues to rise in order to proceed to the next phase.

(2nd slope = water)

Lastly, Water is being vaporized during phase 4. Notice, the temperature is kept constant in order to allow the process to properly occur.

(phase 4 = vaporization)

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The heat of combustion of wood is approximately 16 kJ/g. What is the final temperature that 500.0 mL of water, initially at 25.0

marissa [1.9K]

Answer:

The final temperature is 34,2 ºC when 1,20 g of wood is burned inside the calorimeter.

Explanation:

The heat of combustion of wood which is approximately 16 kJ/g means that 1 g requires 16 kJ of heat so let's calculate about 1,20 g which is the value of wood you have.

1 g ________ 16 kJ

1,20 g ______ 1,20 g x 16 kJ = 19,2 kJ = 19200 J

Now let's apply the calorimetry formula

Q = m . C . ΔT

19200 J = 500 g . 4,186 J/ gºC ( Tfinal - 25ºC)

<em>Look that we don't have the mass of water, instead we have the volume so as you know water density is 1 g/ml, we conclude that in 500 ml, we have 500 g.</em>

On the other hand we convert the 19.2 kJ into J (* 1000) by the units in the value of the specific heat of the water, it is in Joule

19200 J = 500 g . 4,186 J/ gºC ( Tfinal - 25ºC)

19200 J = 2093 J/ºC ( Tfinal - 25ºC)

19200 J = 2093 J/ºC .Tfinal - 52,325 J

19200 J + 52325 J = 2, 093 J/ºC .Tfinal

71525 J = 2093 J/ºC .Tfinal

71525 J /2093 ºC / J = Tfinal = 34,17ºC

8 0

3 years ago

What shape and bond angles would this molecule have in three dimensions?

Darya [45]

Answer : The shape and bond angle of the given molecule is, bent and $120^o$ respectively.

Explanation :

In the given molecule, 'Y' is the central atom and 'X' is the neighboring atom. In the given molecule, there are 4 electron pairs that means the hybridization will be $sp^3$ and the electronic geometry of the molecule will be tetrahedral.

But as there are two atoms around the central atom, the third and fourth position will be occupied by lone pair of electrons. The repulsion between lone and bond pair of electrons is more and hence the molecular geometry will be bent or angular and the bond angle will be, $120^o$ .

Hence, the shape and bond angle of the given molecule is, bent and $120^o$ respectively.

5 0

3 years ago

Read 2 more answers

What were schools like the first half of Henry's life? How do you think this affect his education? Answer BOTH questions in comp

Lorico [155]

Answer:

Not sure.

Explanation:

Who is Henry?

3 0

3 years ago