Answer: W + BgCz2 arrow WCz + Bg
2 W + BgCz2 arrow 2 WCz + Bg
Explanation:
Cz has 2 so you balcne the other side of WCz.
Since you Balcanes the Cz you changed the W and you Balcanes the other W on the left side.
Answer:
The moles of sucrose that are available for this reaction is 0.0292 moles
Explanation:
Combustion is an specifyc reaction where the reactants react with O₂ in order to produce CO₂ and H₂O
This combustion is: C₁₂H₂₂O₁₁ + 12O₂ → 12CO₂ + 11H₂O
We have to conver the mass to moles, to find out the limiting reactant
10 g . 1 mol / 342 g = 0.0292 moles of sucrose
8 g . 1mol / 32g = 0.250 moles of O₂
The moles of sucrose that are available for this reaction is 0.0292 moles
Before we start to work with the equation we must find the limiting reactant. When you find it, you can do all the calculations.
Answer:
B.) The molecule is a branched hydrocarbon.
Explanation:
A hydrocarbon is any molecule made up of carbon and hydrogen exclusively. A methyl- prefix denotes the presence of a methyl group (CH₃), which is situated as a branch off of a hydrocarbon carbon.
<h2>Answer:</h2>
5.65moles
<h2>Explanations:</h2>
The formula for calculating the number of moles the compound contain is given as:
Given the following parameters
Mass of Ag = 700grams
Determine the molar mass of AgO
Molar mass = 107.87 + 16
Molar mass = 123.87g/mol
Determine the moles of AgO
Hence the moles of AgO present is 5.65moles
Answer:
De la Alex;)(da alex ăla de e din cls cu tn:)
