All categories

3 years ago

A young scientist wants to focus on drug creation. What is one of the first things he should do?

1 answer:

8 0

The given question is incomplete as it lacks the appropriate options, however, the options related to this question is as follows:

a)Test a composite material in the lab to see how it can be improved.

b)Look into trends of various diseases and their effects on society.

c)Research available drugs for treating illnesses such as cancer and heart disease, as well as the side effects of these drugs.

d)Make a plan for how to conquer a disease with drugs.

Answer:

The correct answer is - b)Look into trends of various diseases and their effects on society.

Explanation:

The young scientist who wants to focus on creating drugs to treat disease must think and look for the diseases that are needed to be treated at the moment or affecting the population most and how it affects the society and then plan how to do it.

So, the scientist needs to check the trends of various disease and their effect on society for developing understanding which disease needs to be cure first and how it affects.

Thus, the most appropriate answer is - option B.

You might be interested in

Why do heart diseas patient's eat oil instead of fat?

7nadin3 [17]

Answer:

lube

Explanation:

8 0

3 years ago

Read 2 more answers

leonid [27]

Answer:

Which of the following

properties distinguishes a solution

oversaturated with a dilute?

The supersaturated solution is one in which the solvent has dissolved more solute than it can dissolve in the saturation equilibrium. The solute can be a solid, or a gas. The molecules of the solvent surround those of the solute and seek to open space between themselves to be able to harbor more amount of solute.

A dilute solution is a solution that has not reached the maximum concentration of solute dissolved in a solvent. The additional solute will dissolve when added in a dilute solution and will not appear in the aqueous phase. It is considered a state of dynamic equilibrium where the speeds in which the solvent dissolves the solute are greater than the recrystallization rate.

8 0

3 years ago

Which step in naming unsaturated hydrocarbons is used for alkenes but not alkynes?

Slav-nsk [51]

Answer:

Examine the multiple bond for cis- and trans- isomers.

Explanation:

6 0

3 years ago

Read 2 more answers

Which atomic model shows the atom as a positively charged sphere with negatively charged electrons spread throughout

tankabanditka [31]

Answer:

B) Thomson's Model

Explanation:

Dalton's Model simply consisted of small spheres that represented atoms, and Bohr's model had a nucleus in the center with electrons orbiting in strict orbits, not randomly spread throughout. Thomson's plum pudding model, however, had an overall positively charged atom with many electrons spread throughout. If you search up "Plum Pudding Model" you can visually understand this.

If you want further tutoring help in chemistry or other subjects for FREE, check out growthinyouth.org.

5 0

3 years ago

For each of the following balanced oxidation-reduction reactions, (i) identify the oxidation numbers for all the elements in the

AlladinOne [14]

Answer:

Oxidation numbers

I₂O₅(s): I (5+); O(2-)

CO(g): C(2+); O(2-)

I₂(s): I(0)

CO₂(g): C(4+); O(2-)

Oxidation numbers

Hg²⁺(aq): Hg(2+)

N₂H₄(aq): N(2-); H(1+)

Hg(l): Hg(0)

N₂(g): N(0)

H⁺(aq): H(1+)

Oxidation numbers

H₂S(aq): H(1+); S(2-)

H⁺(aq): H(1+)

NO₃⁻(aq): N(5+); O(2-)

S(s): S(0)

NO(g): N(2+); O(2-)

H₂O(l): H(1+); O(2-)

Explanation:

In order to state the total number of electrons transferred we have to identify both half-reactions for each redox reaction.

1. I₂O₅(s) + 5 CO(g) → I₂(s) + 5 CO₂(g)

Oxidation: 10 e⁻ + 10 H⁺(aq) + I₂O₅(s) → I₂(s) + 5 H₂O(l)

Reduction: 5 H₂O(l) + 5 CO(g) → 5 CO₂(g) + 10 H⁺(aq) + 10 e⁻

2. 2 Hg²⁺(aq) + N₂H₄(aq) → 2 Hg(l) + N₂(g) + 4 H⁺(aq)

Oxidation: N₂H₄(aq) → N₂(g) + 4 H⁺(aq) + 4 e⁻

Reduction: 2 Hg²⁺(aq) + 4 e⁻ → 2 Hg(l)

3. 3 H₂S(aq) + 2H⁺(aq) + 2 NO₃⁻(aq) → 3 S(s) + 2 NO(g) + 4H₂O(l)

Oxidation: 3 H₂S(aq) → 3 S(s) + 6 H⁺(aq) + 6 e⁻

Reduction: 8 H⁺(aq) + 2 NO₃⁻(aq) + 6 e⁻ → 2 NO(g) + 4 H₂O

5 0

3 years ago