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emmasim [6.3K]
2 years ago
15

8. Somebody said the answer is letter A. I Don't Know the answer

Mathematics
1 answer:
zloy xaker [14]2 years ago
5 0

Answer:

D. Addition Property of Equality; Subtraction Property of Equality

Step-by-step explanation:

Answer:

Option C and B

Step-by-step explanation:

In the question step C is 23 + 11 = -11 +(-4x) + 11

which is in the form of a + b = c + a

In step C we have added 11 on both the sides to eliminate 11 from right side of the equation.

property which signifies this step is

Addition property of equality :

In step 'f' expression is

\frac{34}{-4}=\frac{-4x}{-4}

In this step equation has been divided by -4 on both the sides to eliminate 4 from the numerator.

In this step division property of equality has been applied.

Therefore Option C and B are the correct options.

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In which choice is y not a linear function of x?
Nadya [2.5K]

Answer:D

Step-by-step explanation:

In d the x’s cancel out so y is not a function of x anymore!

3 0
3 years ago
smantha saw twobottles of ketchup at the store for the same price.One bottle contained4 pints of ketchup and the other contained
ss7ja [257]
1.25 quRts is the better bargain!
6 0
3 years ago
What are the roots of this equation? x2-4x+9=0
zysi [14]

Considering the definition of zeros of a function, the zeros of the quadratic function f(x) = x² + 4x +9 do not exist.

<h3>Zeros of a function</h3>

The points where a polynomial function crosses the axis of the independent term (x) represent the so-called zeros of the function.

In summary, the roots or zeros of the quadratic function are those values ​​of x for which the expression is equal to 0. Graphically, the roots correspond to the abscissa of the points where the parabola intersects the x-axis.

In a quadratic function that has the form:

f(x)= ax² + bx + c

the zeros or roots are calculated by:

x1,x2=\frac{-b+-\sqrt{b^{2}-4ac } }{2a}

<h3>This case</h3>

The quadratic function is f(x) = x² + 4x +9

Being:

  • a= 1
  • b= 4
  • c= 9

the zeros or roots are calculated as:

x1=\frac{-4+\sqrt{4^{2}-4x1x9 } }{2x1}

x1=\frac{-4+\sqrt{16-36 } }{2x1}

x1=\frac{-4+\sqrt{-20 } }{2x1}

and

x2=\frac{-4-\sqrt{4^{2}-4x1x9 } }{2x1}

x2=\frac{-4-\sqrt{16-36 } }{2x1}

x2=\frac{-4-\sqrt{-20} }{2x1}

If the content of the root is negative, the root will have no solution within the set of real numbers. Then \sqrt{-20} has no solution.

Finally, the zeros of the quadratic function f(x) = x² + 4x +9 do not exist.

Learn more about the zeros of a quadratic function:

brainly.com/question/842305

brainly.com/question/14477557

#SPJ1

6 0
1 year ago
What is the constant of proportionality from this table?
zloy xaker [14]

Answer:

k = 5

Step-by-step explanation:

k = constant

3 0
2 years ago
A restaurant has 6 pizza toppings to choose from. How many different 2 topping pizzas are possible?
vampirchik [111]
There are 15 possible combinations
8 0
3 years ago
Read 2 more answers
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