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Simora [160]
2 years ago
7

What is 7/4 as a mixed number

Mathematics
1 answer:
devlian [24]2 years ago
6 0
The answer is 1 3/4 or 1.75 depends on how u want it
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POSSIBLE POINTS 10
Sergio039 [100]

Answer:

Minimum: 8 Q1: 14 Median: 17.5 Q3: 30 Maximum: 32

Step-by-step explanation:

8, 9, 11, 14, 17, 23, 29,30, 32, 32

6 0
3 years ago
Bill is golfing with three friends and can either buy generic golf tees that are packaged by the dozen or the higher quality Aer
natka813 [3]

Answer: at lease 8 packages of Aero flight tees.

Step-by-step explanation:

At least 10 golf tees for each member of his foursome = total of at least 4*10 = 40 tees.

2 packages of the generic golf tees, that are packaged by the dozen = 2*12 = 24 tees.

So, Bill must buy at least 16 Aero tees.

This means he must buy 8 pairs

7 0
3 years ago
What is the answer to -30x+100=-22x+140
harina [27]

Answer:

x=-5

Step-by-step explanation:

Add 22x to both sides: -8x+100=140

Subtract 100 from both sides: -8x=40

Divide both sides by -8: x=-5

So the answer is x=-5

5 0
3 years ago
Read 2 more answers
Carl is raising money for his football team. He is selling chocolate bars for $1.50 each and cookies for $2. He sold all 20 of h
stich3 [128]

Answer:

Carl has to sell at least 8 cookies.

c\geq 7.5

Step-by-step explanation:

Carl gets \$1.50 by selling 1 chocolate bar.

Earning from chocolate bars:

Total\ chocolate\ bar=20\\\\Earning\ from\ one\ chocolate\ bar=\$1.50\\\\Total\ earning\ from\ chocolate\ bar=Total\ chocolate\ bar\times cost\ of\ 1\ chocolate\ bar=20\times 1.5=\$30

Earning From cookies:

Let\ total\ number\ of\ cookies=c\\\\Cost\ of\ 1\ cookie=\$2\\\\Earning\ from\ cookies=2\times c=2c

Total\ earning=Earning\ from\ cookies+Earning\ from\ cookies+Earning\ from\ chocolate\ bars\\\\Total\ earning=30+2c

Carl wants to raise at least \$55

Total\ earning\geq 55\\\\2c+30\geq 55\\\\2c\geq 55-30\\\\2c\geq 15\\\\c\geq7.5

7 0
3 years ago
Is this an example of a horizontal asymptote?
8_murik_8 [283]

Answer:

Step-by-step explanation:

Hi there,

The graph indicated is showing a horizontal asymptote. In fact, it is showing both a horizontal and a <em>vertical </em>asymptote.

To tell which type it is, notice where the graph "shoots off" and almost forms an imaginary straight line in one direction. Using this logic, the horizontal asymptote will be exactly horizontal, parallel to x-axis, and vertical asymptote will be exactly vertical, parallel to y-axis.

With this graph, we notice the horizontal asymptote is at y=0, where the x-axis is. The vertical asymptote is bit more difficult to determine graphically, but can definitely say it is past x=-10. We could determine it if we had the function, but that is not necessary for this question.

Study well, and persevere. If you liked this solution, leave a Thanks or give a rating!

thanks,

6 0
3 years ago
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