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3 years ago

Free brainlest just thank my other questions

Chemistry

2 answers:

mihalych1998 [28]3 years ago

8 0

Answer: Heading to now! tyvm :)

Explanation:

alexandr402 [8]3 years ago

6 0

Answer:

ok and thank you for free point

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Which element(s) are not balanced in this equation?

poizon [28]

The correct response is A. Only the Fe is unbalanced.

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3 years ago

List the factor on which Ka of a weak acid depends

lakkis [162]

I don’t know this, so I did research, so here! This is from a website called “Quora”, btw!
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3 years ago

A reaction mixture initially contains 0.140 MCO and 0.140 MH2O. What will be the equilibrium concentration of CO?

Allushta [10]

Answer:

0.013 M

Explanation:

From the question, we can make the following deductions; we are given mixture that contains two compounds, that is A and B, 0.140 M CO and 0.140 M H2O respectively. Then, we are asked to find the equilibrium concentration of Carbonmonoxide,CO.

So, the equation for the reaction is given below;

CO + H2O <-----------------> CO2 + H2.

Initially: we have 0.14M of CO, 0.14M of H2O and zero (0) concentration of CO2 and H2.

At time,t = CO =0.14 - x , H2O = 0.14 - x, CO2 and H2 = x.

The above reaction consist of the forward reaction and the backward reaction.

Therefore, the equilibrium Concentration of CO;

(Since we are giving that Kc = 102). Then, Kc= [CO2][H2] ÷ [CO][H2O]. Where Kc is the equilibrium constant.

Therefore, 102 = [x^2] / [0.14 - x]^2.

==> 10.1= x/0.14 - x.

====> 0.141 - 10.1 x = x.

x + 10.1 x = 0.141.

===> 11.1 x = 0.141.

===> x = 0.141 ÷ 11.1.

===> x = 0.127 M .

Then, at time,t CO = 0.14 - x.

= 0.14 - 0.127 = 0.013 M

8 0

3 years ago

Read 2 more answers

HELP ASAP

arlik [135]

Answer:

He's flying and was looking

Explanation:

6 0

3 years ago

A ridged steel tank filled with 62.7L of nitrogen gas of 85.0L atm

mylen [45]

The final gas pressure : 175.53 atm

<h3>Further explanation</h3>

Maybe the complete question is like this :

A ridged steel tank filled with 62.7 l of nitrogen gas at 85.0 atm and 19 °C is heated to 330 °C while the volume remains constant. what is the final gas pressure?

The volume remains constant⇒Gay Lussac's Law

<em>When the volume is not changed, the gas pressure in the tube is proportional to its absolute temperature </em>

$\tt \dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}$

P₁=85 atm

T₁=19+273=292 K

T₂=330+273=603 K

$\tt P_2=\dfrac{P_1\times T_2}{T_1}\\\\P_2=\dfrac{85\times 603}{292}\\\\P_2=175.53~atm$

8 0

2 years ago