Answer:
1. 
2. 
Explanation:
Hello,
1.) By coupling the given reaction with the formation of carbon dioxide, one states the total reaction as:
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2.) Now, since we know that the Gibbs free energy for the decomposition of the metal is 288.5kJ/mol and the Gibbs free energy for the formation of carbon dioxide has a value of −394.39kJ/mol, the total Gibbs free energy for this process is:
Δ
So the equilibrium constant is:
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The concentration of OH- ( symbol: [OH-] ), is equal to 10^-pOH (ten to the pOH'th power). The pOH equals 14 minus the pH, because the pH + the pOH = 14. So the pOH is 14-13= 1. Now the concentration of OH- is 10^-1 (= 1) moles/Litre
<span>NaOH (s) --> Na+ (aq) + OH- (aq) </span>
<span>1. : 1. : 1 </span>
<span>So by dissolving one mole of NaOH, you get one mole of Na+ and one mole of OH-. Meaning that the molarity (number of solved NaOH in one Litre) of NaOH is 1 mole/Litre, because the ratio is 1:1. This means, in ten litres of water there are also ten moles of NaOH. And the weight of one mole of NaOH is 40.00 grams (look it up in literature). So in ten litres solution with a pH of 13, there are 40.00*10 = 400 = 4 * 10^2 grams of NaOH dissolved</span>
Answer:
because the reaction can always be accelerated by heat
<span>(1.35 x 2 x 10^-10 m/atom) = 2.0 x 10^7 atoms</span>
<span>1. Gaseous acetylene (C2H2) reacts with oxygen gas to form gaseous carbon dioxide and gaseous water.
2. Chlorine gas reacts with aqueous potassium iodide to form solid iodine and aqueous potassium chloride.
3. Solid lithium oxide reacts with liquid water to form aqueous lithium hydroxide.
4. Gaseous carbon monoxide reacts with oxygen gas to form carbon dioxide gas.</span>
