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katen-ka-za [31]
2 years ago
8

A biochemical engineer isolates a bacterial gene fragment and dissolves a 10.0-mg sample in enough water to make 30.0 mL of solu

tion. The osmotic pressure of the solution is 0.340 torr at 25°C. (a) What is the molar mass of the gene fragment?
Chemistry
1 answer:
Novay_Z [31]2 years ago
7 0

The molar mass of the gene fragment is 19182 g/mol.

What is osmotic pressure ?

Osmotic pressure is the minimum pressure which needs to be applied to a solution to prevent the inward flow of its pure solvent across a semipermeable membrane. It is also defined as the measure of the tendency of a solution to take in a pure solvent by osmosis. Potential osmotic pressure is the maximum osmotic pressure that could develop in a solution if it were separated from its pure solvent by a semipermeable membrane.

We employ the osmotic pressure equation to determine the solute's concentration, which is:

π = iMRT

Using the values in the equation above, we obtain:  19182 g/mol.

To learn more about gene fragment click on the link below:

brainly.com/question/22426204

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A sample of gaseous neon atoms at atmospheric pressure and 0 °c contains 2.69 * 1022 atoms per liter. the atomic radius of neon
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Explanation

Radius of neon atom : 69 pm = 69\times 10^{-12} m

Volume occupied by the one atom:\frac{4}{3}\pi r^3

=\frac{4}{3}\times 3.14\times(69\times 10^{-12} m)^3=1.37\times 10^{-30} m^3

given that 2.69\times 10^{22} atoms are present in 1L

1 L = 0.001 m^3

The volume occupied by the 2.69\times 10^{22} neon atoms

2.69\times 10^{22}\times 1.37\times 10^{-30} m^3=3.68\times 10^{-8} m^3

Fraction of volume occupied by the neon atom:

=\frac{3.68\times 10^{-8} m^3}{0.001 m^3}=3.68\times 10^{-11} m^3

3.68\times 10^{-11} m^3

The fraction of of volume occupied by the neon atom is very less than the 1 L which indicates the presence of large amount of empty space between the atoms of the gas.

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3 years ago
If a cross-country runner covers a distance of 347 meters in 134 seconds what is her speed?
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time t=134 sec.
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What is special about the kelvin temperature scale
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In an experiment, 16.8 g of k2so4 was dissolved in 1.00 kg of water to make a solution. the freezing point of the solution was m
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Answer is: V<span>an't Hoff factor (i) for this solution is 2,26.
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<span>Kf - molal freezing-point depression constant for water is 1,86°C/m.
</span>m -  molality, moles of solute per kilogram of solvent.
n(K₂SO₄) = 16,8 g ÷ 174,25 g/mol
n(K₂SO₄) = 0,096 mol.
m(K₂SO₄) = 0,096 mol/kg.
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3 years ago
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