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katen-ka-za [31]
1 year ago
8

A biochemical engineer isolates a bacterial gene fragment and dissolves a 10.0-mg sample in enough water to make 30.0 mL of solu

tion. The osmotic pressure of the solution is 0.340 torr at 25°C. (a) What is the molar mass of the gene fragment?
Chemistry
1 answer:
Novay_Z [31]1 year ago
7 0

The molar mass of the gene fragment is 19182 g/mol.

What is osmotic pressure ?

Osmotic pressure is the minimum pressure which needs to be applied to a solution to prevent the inward flow of its pure solvent across a semipermeable membrane. It is also defined as the measure of the tendency of a solution to take in a pure solvent by osmosis. Potential osmotic pressure is the maximum osmotic pressure that could develop in a solution if it were separated from its pure solvent by a semipermeable membrane.

We employ the osmotic pressure equation to determine the solute's concentration, which is:

π = iMRT

Using the values in the equation above, we obtain:  19182 g/mol.

To learn more about gene fragment click on the link below:

brainly.com/question/22426204

#SPJ4

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What is the pressure in a 5.00 L tank with 49.00 grams of oxygen gas at 350 K? ___atm
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Answer:

The right answer is "8.81 atm".

Explanation:

Given:

V = 5.00 L

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MW = 32 g/mol

T = 350 K

Now,

Number of moles will be:

n = \frac{Mass}{MW}

   =\frac{49.00}{32}

   =1.53125 \ mole

By using the ideal gas equation, we get

⇒ PV=nRT

or,

⇒    P=\frac{nRT}{V}

By substituting the values, we get

           =\frac{1.53125\times 0.0821\times 350}{5.00}

           =\frac{44.1}{5.00}

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Explain the difference between qualitative and quantitative properties.
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Qualitative properties are properties that are observed and can generally not be measured with a numerical result. They are contrasted to quantitative properties which have numerical characteristics.
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A sample of gas has an initial pressure of 1.5 atm, an initial volume of 3.0 L, and an initial temperature of 293K. If the final
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Answer:

1.9 L

Explanation:

Step 1: Given data

  • Initial pressure (P₁): 1.5 atm
  • Initial volume (V₁): 3.0 L
  • Initial temperature (T₁): 293 K
  • Final pressure (P₂): 2.5 atm
  • Final volume (V₂): ?
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Step 2: Calculate the final volume of the gas

If we assume ideal behavior, we can calculate the final volume of the gas using the combined gas law.

P₁ × V₁ / T₁ = P₂ × V₂ / T₂

V₂ = P₁ × V₁ × T₂ / T₁ × P₂

V₂ = 1.5 atm × 3.0 L × 303 K / 293 K × 2.5 atm = 1.9 L

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3 years ago
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