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3 years ago

ASAP HELP PLS HELP EXPLAIN IM CONFUSED PLSSS

Mathematics

1 answer:

sertanlavr [38]3 years ago

3 0

Step-by-step explanation:

x+3=12

-3. -3

x=9

awnser is 9

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What is the value of f(-3)

Readme [11.4K]

$f(x)=\left\{\begin{array}{ccc}-2&if&x < -3\\4x&if&-3\leq x\leq-1\\x^2&if&x > -1\end{array}\right\\\\-3\leq-3\leq-1\to f(x)=4x\\\\f(-3)=4(-3)=-12$

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3 years ago

Let a = 0.9876 and b = 0.9887 with N = 2, calculate the midpoint.

rodikova [14]

Answer:

For a=0.9876 and b=0.9887 mid point will be 0.98815

Step-by-step explanation:

We have given a = 0.9876 and b = 0.9887

And N = 2

We have to find the mid point

For finding mid point we know that formula

Midpoint $=\frac{a+b}{2}$ , here we have given a=0.9876 and b = 0.9887

So midpoint will be $=\frac{0.9876+0.9887}{2}=\frac{1.9763}{2}=0.98815$

So for a=0.9876 and b=0.9887 mid point will be 0.98815

5 0

3 years ago

Can you please help me and show you work

Nutka1998 [239]

Answer:

37.50 and 84.97

Step-by-step explanation:

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3 years ago

Avery’s water bottle holds 300 milliliters. Dashawn’s container holds 3/4 as much water how much do both containers hold?

GarryVolchara [31]

Answer: Avery's bottle holds 300 milliliters. If Dashawn's container holds 3/4 as much, then his container can hold 225 milliliters. Added together, both containers can hold 525.

Step-by-step explanation: 3/4 of 300 is 225. 300 + 225 = 525.

7 0

3 years ago

Find 2 common angles that sum to (17pi/12) 2. Evaluate tan(17pi/12) using the sum identity for tangent.

Dmitry [639]

Note that
$\frac{17 \pi }{12} = \frac{3 \pi }{12} + \frac{14 \pi }{12} = \frac{ \pi }{4} + \frac{7 \pi }{6}$

Note that
$x= \frac{ \pi }{4}:\,\, sin(x) =cos(x)= \frac{1}{ \sqrt{2} },\,tan(x)=1\\x= \frac{7 \pi }{6} :\,\,sin(x)=- \frac{1}{2} ,\,\,cos(x)=- \frac{ \sqrt{3} }{2} ,\,\,tan(x)= \frac{1}{ \sqrt{3} }$

Use the identity
$tan(x+y)= \frac{tan(x)+tan(y)}{1-tan(x)tan(y)}$

Therefore
$tan( \frac{17 \pi }{12} )= \frac{1+ \frac{1}{ \sqrt{3} } }{1- \frac{1}{ \sqrt{3} } } = \frac{ \sqrt{3}+1 }{ \sqrt{3}-1} = \frac{( \sqrt{3}+1 )^{2}}{( \sqrt{3}-1 )( \sqrt{3}+1 )} = \frac{3+1+2 \sqrt{3}}{3-1} =2+ \sqrt{3}$

Answer: 2 + √3

8 0

3 years ago