For this equation first you should add +11 on both sides and the add -4/7w so you will have:
3/7w- 4/7w = 11 ⇒ -1/7w = 11 ⇒ w = 11* -7 = -77 so the answer is:
w = -77 :)))
i hope tis is helpful
have a nice day
Answer:
25% of probabilities
Step-by-step explanation:
A= red eye
a=sepia eye
B=longwing
b=apterous
AB aB
Ab AABb AaBb
ab AaBb aaBb
AABb=25%
AaBb=25%
Ab= 25%
aaBb=25%
aaBb= sepia eye with longwig
Answer:
A Pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm and 96 cm but does not resonate at any wavelengths longer than these. This pipe is:
A. closed at both ends
B. open at one end and closed at one end
C. open at both ends.
D. we cannot tell because we do not know the frequency of the sound.
The right choice is:
B. open at one end and closed at one end
.
Step-by-step explanation:
Given:
Length of the pipe,
= 120 cm
Its wavelength
= 480 cm
= 160 cm and
= 96 cm
We have to find whether the pipe is open,closed or open-closed or none.
Note:
- The fundamental wavelength of a pipe which is open at both ends is 2L.
- The fundamental wavelength of a pipe which is closed at one end and open at another end is 4L.
So,
The fundamental wavelength:
⇒ 
It seems that the pipe is open at one end and closed at one end.
Now lets check with the subsequent wavelengths.
For one side open and one side closed pipe:
An odd-integer number of quarter wavelength have to fit into the tube of length L.
⇒
⇒ 
⇒
⇒ 
⇒
⇒ 
⇒
⇒
So the pipe is open at one end and closed at one end
.
Answer:
x=137
y=525-137
y=388
Step-by-step explanation:
Let the student tickets be x
Let the geral Admission tickets be y
x+y=525
y=525-x
4x+6y=2876 (subsitute for y)
4x+6(525-x)=2876
4x+3150-6x=2876
-2x=-274
x=137
y=525-137
y=388
Hence, about 137 childern tickets were sold and 388 gernal admission tickets were sold.
Paul.
8.5 the answer is and replace the areas