LCM of 2 and 5 =10
The LCM of 2 and 5 is the smallest positive integer 10 that is divisible by both 2 and 5 without any remainder.
Answer:
Local minimum at x = 0.
Step-by-step explanation:
Local minimums occur when g'(x) = 0 and g"(x) > 0.
Local maximums occur when g'(x) = 0 and g"(x) < 0.
Set g'(x) equal to 0 and solve:
0 = 2x (x − 1)² (x + 1)²
x = 0, 1, or -1
Evaluate g"(x) at each point:
g"(0) = 2
g"(1) = 0
g"(-1) = 0
There is a local minimum at x = 0.
Answer:
u ok?
Step-by-step explanation:
Answer:
the sum is zero
Step-by-step explanation:
A is equal to 8, B is equal to -8. 8+(-8)=0
Answer:
a) £11.46
b) £8.54
Step-by-step explanation:
a) Ffion's Bill = £2.49 + 2(£3.99) + £0.99
= £2.49 + £7.98 + £0.99
= £11.46
b) Change Received = £20 - £11.46
= £8.54
