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2 years ago

Write an equation of the line that passes through the points (−6,20) and (0, 8).

Mathematics

1 answer:

Natalija [7]2 years ago

8 0

Answer:

y = -2x + 8

Step-by-step explanation:

(−6, 20) and (0, 8)

First you want to find the slope of the line that passes through these points. To find the slope of the line, we use the slope formula: (y₂ - y₁) / (x₂ - x₁)

Plug in these values:

(8 - 20) / (0 - (-6))

Simplify the parentheses.

= (-12) / (6)

Simplify the fraction.

-12/6

= -2

This is your slope. Plug this value into the standard slope-intercept equation of y = mx + b.

y = -2x + b

To find b, we want to plug in a value that we know is on this line: in this case, I will use the second point (0, 8). Plug in the x and y values into the x and y of the standard equation.

8 = -2(0) + b

To find b, multiply the slope and the input of x(0)

8 = 0 + b

b = 8

Plug this into your standard equation.

y = -2x + 8

This is your equation.

Check this by plugging in the other point you have not checked yet (-6, 20).

y = -2x + 8

20 = -2(-6) + 8

20 = 12 + 8

20 = 20

Your equation is correct.

Hope this helps!

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Factor completely 3x3 − 6x2 − 24x. 3x(x − 4)(x + 2) 3x(x + 4)(x − 2) 3x(x − 3)(x − 2) 3x(x + 3)(x − 2)

inysia [295]

Answer:

3x(x - 4)(x + 2)

Step-by-step explanation:

Given

3x³ - 6x² - 24x ← factor out common factor of 3x from each term

= 3x(x² - 2x - 8) ← factor the quadratic

Consider the factors of the constant term (- 8) which sum to give the coefficient of the x- term.

The factors are - 4 and + 2, since

- 4 × 2 = - 8 and - 4 + 2 = - 2, thus

x² - 2x - 8 = (x - 4)(x + 2) and

3x³ - 6x² - 24x = 3x(x - 4)(x + 2)

7 0

3 years ago

Describe a real-world situation that could be modeled by dividing two rational numbers.

34kurt

Answer:

Dave got the entire office a loaf of bread and it has 11 slices. There where 4 other people that got the bread including dave how many slices would each person get?

Step-by-step explanation:

just divide 11 by 4

7 0

3 years ago

Which one is right triangle angle <br>a. 45, 55 and 35<br>b. 52, 48 and 20

Gemiola [76]

<h2>option b. 52, 48 and 20</h2>

Step-by-step explanation:

<u>let's solve:-</u>

To test whether given this triangle is right triangle or not, we can use the Pythagorean Theorem .

soo

Pythagorean Theorem=

$\bold \green{(leg1)^{2} +(leg2)^{2} =(hypotenuse)^{2} }$

Here:-

$\bold \blue{leg \: 1 = 48} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \bold \blue{ leg2 = 20} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \bold\blue{hypotenuse = 52}$

Putting values:-

${48}^{2} + {20}^{2} = {52}^{2} \: \: \: \: \: \: \\ \\ 2304 + 400 = 2704 \\ \\ 2704 = 2704 \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

4 0

2 years ago

Use the Taylor series you just found for sinc(x) to find the Taylor series for f(x) = (integral from 0 to x) of sinc(t)dt based

Marina CMI [18]

In this question (brainly.com/question/12792658) I derived the Taylor series for $\mathrm{sinc}\,x$ about $x=0$ :

$\mathrm{sinc}\,x=\displaystyle\sum_{n=0}^\infty\frac{(-1)^nx^{2n}}{(2n+1)!}$

Then the Taylor series for

$f(x)=\displaystyle\int_0^x\mathrm{sinc}\,t\,\mathrm dt$

is obtained by integrating the series above:

$f(x)=\displaystyle\int\sum_{n=0}^\infty\frac{(-1)^nx^{2n}}{(2n+1)!}\,\mathrm dx=C+\sum_{n=0}^\infty\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}$

We have $f(0)=0$ , so $C=0$ and so

$f(x)=\displaystyle\sum_{n=0}^\infty\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}$

which converges by the ratio test if the following limit is less than 1:

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(-1)^{n+1}x^{2n+3}}{(2n+3)^2(2n+2)!}}{\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}}\right|=|x^2|\lim_{n\to\infty}\frac{(2n+1)^2(2n)!}{(2n+3)^2(2n+2)!}$

Like in the linked problem, the limit is 0 so the series for $f(x)$ converges everywhere.

7 0

3 years ago

What two numbers add to 9 and multiply to -70

Alborosie

X, y - the numbers

The numbers add to 9 and multiply to -70.
$x+y=9 \\
xy=-70 \\ \\
y=9-x \\
xy=-70 \\ \\
\hbox{substitute 9-x for y in the second equation:} \\
x(9-x)=-70 \\
9x-x^2=-70 \\
-x^2+9x+70=0 \\
-x^2+14x-5x+70=0 \\
-x(x-14)-5(x-14)=0 \\
(-x-5)(x-14)=0 \\
-x-5=0 \ \lor \ x-14=0 \\
x=-5 \ \lor \ x=14 \\ \\
y=9-x \\
y=9-(-5) \ \lor \ y=9-14 \\
y=14 \ \lor \ y=-5 \\ \\
(x,y)=(-5,14) \hbox{ or } (x,y)=(14,-5)$

The numbers are -5 and 14.

4 0

3 years ago