Answer:
Small box weighs 13.75 kg & large box weighs 15.75 kg
Step-by-step explanation:
We can write 2 simultaneous equation and solve for weight of each box.
<em>Let weight of large box be l and small box be s.</em>
<em />
"<u>3 large boxes and 5 small boxes has a total weight of 116 kilograms</u>":
and
"<u>9 large boxes and 7 small boxes has a total weight of 238 kilograms</u>":
<em>Now we can solve for l in the 1st equation and put it into 2nd equation and get s:</em>
<em>
</em>
<em>now,</em>
<em>
</em>
<em />
<em>now we plug in 13.75 into s into equation of l to find s:</em>
<em>
</em>
Answer: 1726
Step-by-step explanation:
A=2(wl+hl+hw)
A=
2
w
l
h
l
h
w
=
2
6.5
29
19
29
19
6.5
=
1726
Given Information:
Population mean = p = 60% = 0.60
Population size = N = 7400
Sample size = n = 50
Required Information:
Sample mean = μ = ?
standard deviation = σ = ?
Answer:
Sample mean = μ = 0.60
standard deviation = σ = 0.069
Step-by-step explanation:
We know from the central limit theorem, the sampling distribution is approximately normal as long as the expected number of successes and failures are equal or greater than 10
np ≥ 10
50*0.60 ≥ 10
30 ≥ 10 (satisfied)
n(1 - p) ≥ 10
50(1 - 0.60) ≥ 10
50(0.40) ≥ 10
20 ≥ 10 (satisfied)
The mean of the sampling distribution will be same as population mean that is
Sample mean = p = μ = 0.60
The standard deviation for this sampling distribution is given by
Where p is the population mean that is proportion of female students and n is the sample size.
Therefore, the standard deviation of the sampling distribution is 0.069.
Answer:
Step-by-step explanation:
A = LW + ½πr²
A = 15(12) + ½(3.14)(12²/4)
A = 180 + 56.52
A = 236.52 m²
Answer:
1.542425 or 4
Step-by-step explanation:
