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skelet666 [1.2K]
3 years ago
7

What is perpendicular? What is parallel? And what are the differences between the two?

Mathematics
1 answer:
prohojiy [21]3 years ago
5 0
So a parallel line is were the lines never meet but the perpendicular line meet at a right angle
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Tell whether x and y show direct variation. Explain your reasoning. y−x=0
Jlenok [28]

Answer:

yes

Step-by-step explanation:

Direct variation is represented as

y = kx, where k is a constant.  

We can rewrite y - x = 0 as

    y = x   (add x to both sides)

This can be looked at as

  y = (1)x     , so this is a direct variation relationship where k = 1

7 0
3 years ago
Please write complete and right answer
e-lub [12.9K]

1111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111117111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111

where is the different number?

4 0
2 years ago
Complete the statement 36x^3a+45xa^2=9xa
Lorico [155]
<span>36x³a + 45xa² =</span>9xa(4x²+5a)
7 0
3 years ago
Help me please thank you
MariettaO [177]
(x+4)+135.8=180.0
-135.8.-135.8

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7 0
3 years ago
Pre-calc, image attached
makvit [3.9K]

Answer:

\lim_{x \to 7} \frac{\sqrt{x+2}-3 }{x-7} = \frac{1}{6}

Step-by-step explanation:

\lim_{x \to 7} \frac{\sqrt{x+2}-3 }{x-7}

\frac{\sqrt{x+2}-3 }{x-7}

\frac{\frac{1}{2} (x+2)^{-\frac{1}{2} }}{1} <-- Take derivative of numerator and denominator expressions

{\frac{1}{2} (x+2)^{-\frac{1}{2} }} <-- Simplify

\frac{1}{2}(\frac{1}{\sqrt{x+2} }) <-- Rewrite

\frac{1}{2}(\frac{1}{\sqrt{7+2} }) <-- Use direct substitution and plug in the limit x=7

\frac{1}{2}(\frac{1}{\sqrt{9} })

\frac{1}{2}(\frac{1}3 })

\frac{1}{6}

Therefore, \lim_{x \to 7} \frac{\sqrt{x+2}-3 }{x-7} = \frac{1}{6}

4 0
2 years ago
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