If you use the pothaorian theorym (A squared + B squared= C squared) youll be able to figure out the right answer is 65.
Answer:
80 tickets
Step-by-step explanation:
Given the profit, y, modeled by the equation, y = x^2 – 40x – 3,200, where x is the number of tickets sold, we are to find the total number of tickets, x, that need to be sold for the drama club to break even. To do that we will simply substitute y = 0 into the given the equation and calculate the value of x;
y = x^2 – 40x – 3,200,
0 = x^2 – 40x – 3,200,
x^2 – 40x – 3,200 = 0
x^2 – 80x + 40x – 3,200 = 0
x(x-80)+40(x-80) = 0
(x+40)(x-80) = 0
x = -40 and x = 80
x cannot be negative
Hence the total number of tickets, x, that need to be sold for the drama club to break even is 80 tickets
Answer:
And we can find the probability with the complement rule and the normal standard distirbution and we got:
Step-by-step explanation:
Let X the random variable that represent the time spent reading of a population, and for this case we know the distribution for X is given by:
Where
and
We are interested on this probability
And we can use the z score formula given by:
Using this formula we got:
And we can find the probability with the complement rule and the normal standard distirbution and we got:
Answer:
2nd debate was 3 hours long.
Step-by-step explanation:
We have been given that during the mayoral election,two debates were held between the candidates. The first debate lasted 1 2/3 hours. The second one was 1 4/5 times as long as the first one.
Let us find the estimate of time spent on 2nd debate.
1 2/3 hours would be approximately 2 hours. 1 4/5 times would be equal to 2 times.

Therefore, the estimated time is less 4 hours.
To find the time spent on 2nd debate, we will multiply 1 2/3 by 1 4/5.
First of all, we will convert mixed fractions into improper fractions as:


Now, we will multiply both fractions as:



Therefore, the 2nd debate was 3 hours long.
First you must know that for remarkable angles: cos (0) = 1, cos (π) = - 1, cos (π / 2) = 0, cos (3π / 2) = 0, cos (2π) = 1. Then, by simple substitution in the given formula, you can find the solutions of x. Which for the interval [0, 2π) are: x = π, x = pi divided by two and x = three pi divided by two.Attached solution.