How many odd three-digit numbers can you make up of five cards with the numbers 1, 2, 3, 5, 6?

How do the mathematical domain and reasonable domain compare

dexar [7]

---
weekly income y:
y = 10x
where x is number of hours worked per week
---
domain: x >= 0 hours
range: y >= 0 dollars
---
Solve and graph linear equations:
https://sooeet.com/math/linear-equation-solver.php
---

3 0

3 years ago

An ice cream factory makes 170 quarts of ice cream in 2 hours how many quarts could be made in 36 hours what was that rate per d

Katyanochek1 [597]

170 quarts/2 hours = 85 quarts/hour

85 quarts/hour * 36 hours = 3060 quarts

85 quarts/hour * 24 hours = 2040 quarts

8 0

3 years ago

Find the area of this parallelogram?

Jet001 [13]

So, the area of a parallelogram is the base times the height or

$a = b \times h$

a being area

b being base

h being height

the height is 8 cm and the base is 15 cm

(remember: the heght should be perpendicular to the base)

so we plug in 8 for h and 15 for b to get

$a = 15 \times 8$

and 15 × 8 = (10 × 8) + (5 × 8) = 80 + 40 =120

So the answer is 120

3 0

3 years ago

Please help me please

Contact [7]

Answer:

458

Step-by-step explanation:

6 0

3 years ago

In a certain computer, the probability of a memory failure is 0.01, while the probability of a hard disk failure is 0.02. If the

ratelena [41]

Answer:

We need to remember that we have independent events when a given event is not affected by previous events, and we can verify if two events are independnet with the following equation:

$P(A \cap B) = P(A) *P(B)$

For this case we have that:

$P(A) *P(B) = 0.01*0.02= 0.0002$

And we see that $0.0002 \neq P(A \cap B)$

So then we can conclude that the two events given are not independent and have a relationship or dependence.

Step-by-step explanation:

For this case we can define the following events:

A= In a certain computer a memory failure

B= In a certain computer a hard disk failure

We have the probability for the two events given on this case:

$P(A) = 0.01 , P(B) = 0.02$

We also know the probability that the memory and the hard drive fail simultaneously given by:

$P(A \cap B) = 0.0014$

And we want to check if the two events are independent.

We need to remember that we have independent events when a given event is not affected by previous events, and we can verify if two events are independnet with the following equation:

$P(A \cap B) = P(A) *P(B)$

For this case we have that:

$P(A) *P(B) = 0.01*0.02= 0.0002$

And we see that $0.0002 \neq P(A \cap B)$

So then we can conclude that the two events given are not independent and have a relationship or dependence.

8 0

3 years ago