In this question, you are given 3 separate vegetables without single price. If you want to solve it step by step, it will be easier to count each vegetable price before hand. The price would be:
Cucumber: 2$/6 pieces= $0.33 /piece
Pepper: $9/12 pieces= $0.75/piece
Tomatoes: 4$/6 pieces= $0.66/piece
Then the total cost for the chef shopping item would be: 9 * $0.33 + 18 * $0.75 + 21* $0.66= $3 + $13.5+ $14= $30.5
Answer:
41
Step-by-step explanation:
x=12
so y=3⋅12 +5
=36+5
=41
The correct answer to your problem is 96
We can use the binomial theorem to find the probability that 0 out of the 15 samples will be defective, given that 20% are defective.
P(0/15) = (15C0) (0.2)^0 (1 - 0.2)^15 = (1)(1)(0.8)^15 = 0.0352
Then the probability that at least 1 is defective is equal to 1 - 0.0352 = 0.9648. This means there is a 96.48% chance that at least 1 of the 15 samples will be found defective. This is probably sufficient, though it depends on her significance level. If the usual 95% is used, then this is enough.
I would be 506.110 cause if it is over five then round it to ten