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3 years ago

HELP!!!!! ASAP!!! WILL GIVE %) POINTS AND BRAINLIEST!!!!!

Mathematics

2 answers:

bulgar [2K]3 years ago

5 0

Answer:

The cost represent the slope.

Explanation:

The slope is a constant rate of change. For one day at Cheap-o-Rentals, the cost is $39. So, that tells us that they have only given the cost of 1 day, which means as the days pass on, the slope changes along with it.

Thepotemich [5.8K]3 years ago

4 0

The cost per mile driven represents the slope of the function. So b. 15 cents per mile driven is the slope-the price increases as the number of miles increase.

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I'LL MARK BRAINLYIST!!!

puteri [66]

Answer:

The inequality is:

9b + 29b ≤ 20

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2 years ago

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For every 5 yard you run jill run 6 yard if you have run 30 yard then how far jill run.

liubo4ka [24]

Jill has ran 36 yards.
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3 years ago

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100 points for this question I beg

lisov135 [29]

Answer:

22°

Step-by-step explanation:

Refer to picture

Added angles a and b as interior angles of same triangle with angle x to make solving simple.

Angle a is same as 42° since both angles intercept same arc AB.

a = 42°

Angle b is supplementary with 64° angle as linear pair

b = 180° - 64° = 116°

Some of the interior angles of a triangle is 180

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2 years ago

Multiple-Choice Integration, Picture Included, Please Include Work

ValentinkaMS [17]

$\displaystyle\int_0^2\sqrt{4-x^2}\,\mathrm dx$

Recall that a circle of radius 2 centered at the origin has equation

$x^2+y^2=4\implies y=\pm\sqrt{4-x^2}$

where the positive root gives the top half of the circle in the x-y plane. The definite integral corresponds to the area of the right half of this top half. Since the area of a circle with radius $r$ is $\pi r^2$ , it follows that the area of a quarter-circle would be $\dfrac{\pi r^2}4$ .

You have $r=2$ , so the definite integral is equal to $\dfrac{2^2\pi}4=\pi$ .

Another way to verify this is to actually compute the integral. Let $x=2\sin u$ , so that $\mathrm dx=2\cos u\,\mathrm du$ . Now

$\displaystyle\int_0^2\sqrt{4-x^2}\,\mathrm dx=\int_0^{\pi/2}\sqrt{4-(2\sin u)^2}(2\cos u)\,\mathrm du=4\int_0^{\pi/2}\cos^2u\,\mathrm du$

Recall the half-angle identity for cosine:

$\cos^2u=\dfrac{1+\cos2u}2$

This means the integral is equivalent to

$\displaystyle2\int_0^{\pi/2}(1+\cos 2u)\,\mathrm du=2u+\sin2u\bigg|_{u=0}^{u=\pi/2}=\pi$

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3 years ago

Can someone help me to solve this question sec(x)sin(x)-2sin(x)=0 [0,2pi) ? ASAP!!!!!

BigorU [14]

Answer:

x = 0, π/3, π, 5π/3

Step-by-step explanation:

sec(x)sin(x) - 2sin(x) = 0

factor out sin(x)

sin(x)[sec(x) - 2] = 0

then solve by splitting into two parts:

sin(x) = 0 and sec(x) - 2 = 0

x = 0, π and x = π/3, 5π/3 then plug in to original equation to check

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4 years ago