Gravitational potential energy is always calculated with

Which of these is a landform created due to erosion by glaciers? Delta Horn Sandbars Spit

Marina CMI [18]

Answer:

The answer is option B, horn.

Explanation:

The landform horn was formed because when glaciers erode down to form a sharp peak which is called a horn. All of the other options are false because none of those land forms are formed because of the erosion of glaciers

4 0

3 years ago

A positive point charge Q1 = 2.5 x 10-5 C is fixed at the origin of coordinates, and a negative point charge Q2 = -5.0 x 10-6 C

mario62 [17]

Answer:

3.62 m and - 1.4 m

Explanation:

Consider a location towards the positive side of x-axis beyond the location of charge Q₂

x = distance of the location from charge Q₂

d = distance between the two charges = 2 m

For the electric field to be zero at the location

E₁ = Electric field by charge Q₁ at the location = E₂ = Electric field by charge Q₂ at the location

$\frac{kQ_{1}}{(2 + x)^{2}}= \frac{kQ_{2}}{x^{2}}$

$\frac{2.5\times 10^{-5}}{(2 + x)^{2}}= \frac{5 \times 10^{-6}}{x^{2}}$

x = 1.62 m

So location is 2 + 1.62 = 3.62 m

Consider a location towards the negative side of x-axis beyond the location of charge Q₁

x = distance of the location from charge Q₁

d = distance between the two charges = 2 m

For the electric field to be zero at the location

E₁ = Electric field by charge Q₁ at the location = E₂ = Electric field by charge Q₂ at the location

$\frac{kQ_{1}}{(x)^{2}}= \frac{kQ_{2}}{ (2 + x)^{2}}$

$\frac{2.5\times 10^{-5}}{(x)^{2}}= \frac{5 \times 10^{-6}}{(2+x)^{2}}$

x = - 1.4 m

6 0

4 years ago

What is the value of the angle of refraction of light from a crown glass slab when the angle of incidence is 50°? The slab has a

Artemon [7]

The angle of refraction is $30.3^{\circ}$

Explanation:

Refraction is a wave phenomenon that occurs when a light wave passes through the interface between two mediums. When this occurs, the speed and the direction of the light wave change.

We can find the final direction of the refracted light in this problem by applying Snell's law:

$n_i sin \theta_i = n_r sin \theta_r$