Answer:
The third particle should be at 0.0743 m from the origin on the negative x-axis.
Explanation:
Let's assume that the third charge is on the negative x-axis. So we have:

We know that the electric field is:

Where:
- k is the Coulomb constant
- q is the charge
- r is the distance from the charge to the point
So, we have:

Let's solve it for r(3).
Therefore, the third particle should be at 0.0743 m from the origin on the negative x-axis.
I hope it helps you!
Time period = time/no. of waves = 6/3 = 2s
Answer:
180.4 m
Explanation:
The package in relation to the point where it was released falls a certain distance that is calculated by applying the horizontal motion formulas , as the horizontal speed of the plane and the height above the ground are known, the time that It takes the package to reach its destination and then the horizontal distance (x) is calculated from where it was dropped, as follows:

h = 100 m
x =?
Height formula h:

Time t is cleared:


t = 4.51 sec
Horizontal distance formula x:

x = 40 m / sec x 4.51 sec
x = 180.4 m
A, something to remember is that if the numbers are even the answer too will be even. Every time hope this helps :>