Question

Solid cesium iodide has the same kind of crystal structure as CsCl which is pictured below: If the edge length of the unit cell is 456.2 pm, what is the density of CsI in g/cm3.

Answer 1

The question is incomplete, here is the complete question:

Solid cesium iodide has the same kind of crystal structure as CsCl which is pictured below: If the edge length of the unit cell is 456.2 pm, what is the density of CsI in $g/cm^3$

The image is attached below.

Answer: The density of CsI is $9.09g/cm^3$

Explanation:

To calculate the density of metal, we use the equation:

$\rho=\frac{Z\times M}{N_{A}\times a^{3}}$

where,

$\rho$ = density

Z = number of atom in unit cell = 2  (BCC)

M = atomic mass of CsI = 259.8 g/mol

$N_{A}$ = Avogadro's number = $6.022\times 10^{23}$

a = edge length of unit cell = $456.2pm=456.2\times 10^{-10}cm$    (Conversion factor:  $1cm=10^{10}pm$  )

Putting values in above equation, we get:

$\rho=\frac{1\times 259.8}{6.022\times 10^{23}\times (456.2\times 10^{-10})^3}\\\\\rho=9.09g/cm^3$

Hence, the density of CsI is $9.09g/cm^3$