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UNO [17]
3 years ago
8

how to determine the aspects for core and valence electrons in a periodic table. How comes in some elements like cobalt the 3d i

s on the valence side and arsenic the 3d is on the core side.​
Chemistry
1 answer:
dusya [7]3 years ago
5 0

Answer:

See explanation

Explanation:

The electron configuration of an atom in an element determines the property of the atom. The core electrons are found inside the atom while the valence electrons are found on the outermost shell of the atom.

For cobalt, the outermost shell electron configuration is; [Ar] 3d7 4s2. The 3d7 and 4s2 are found in the valence shell of cobalt.

For arsenic, the electronic configuration is [Ar] 3d¹⁰ 4s² 4p³. The valence electrons are 4s2, 4p3. The 3d electrons are found inside the arsenic atom.

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42. Proton and electuron.
Sauron [17]

Answer:

Protons:

- positive

- aka cation

- in the nucleus along with the neutrons

Electrons:

- negative

- aka anion

- situated in the orbital shells/configuration levels (there are many names)

7 0
2 years ago
In the reaction N2O4(g) 2NO2(g), what changes in color would you expect as pressure is increased at constant temperature?
skelet666 [1.2K]

Answer:

Brown color of the solution decreases

Explanation:

NO_2 is brown in color whereas N_2O_4 is colorless.

Equilibrium reaction between NO_2 and N_2O_4 is as follows:

2NO_2\leftrightharpoons N_2O_4

As per the Le Chatelier's principle, if pressure of a equilibrium is increased, the equilibrium will shift in the direction having fewer no. of moles of gases.

In the given equilibrium, NO_2 side has more no. of moles. So on increasing pressure, equilibrium will shift towards the side of N_2O_4 or more formation of N_2O_4 will take place.

Therefore, more NO_2 will decompose that will decrease the brown color of the solution as N_2O_4 is colorless.

6 0
3 years ago
An experiment produced 0.10 g CO2, with a volume of 0.056 L at STP. If the accepted density of CO2 at STP is 1.96 g/L, what is t
Pachacha [2.7K]
The density of CO2 getting from experiment is 0.1/0.056 = 1.79 g/L. The percent error of this is (1.96 -1.79)/1.96*100%=8.67%. So the approximate percent error is 8.67%.
3 0
3 years ago
According to your study unit, what's the payoff that keeps volunteers using their own time to help their communities?
klasskru [66]
C. It's so rewarding, people feel emotionally high and fulfilled when they're done.

In volunteering, your primary motivation is to extend your help or assistance and make other people happy. Seeing people happy because of what you are doing, it the ultimate reward of volunteering. Happiness gained from this experience is priceless. It is worth more than any freebies or any material gains you will receive. 
8 0
3 years ago
Calcium cyclamate, Ca(C₆H₁₁NHSO₃)₂, is an artificial sweetener used in many countries around the world but is banned in the Unit
xeze [42]

Answer:

2HC₆H₁₁NHSO₃ + BaCO₃ → Ba(C₆H₁₁NHSO₃)₂ + H₂CO₃;

Ba(C₆H₁₁NHSO₃)₂ + H₂SO₄ → BaSO₄ + 2HC₆H₁₁NHSO₃;

2HC₆H₁₁NHSO₃ + Ca(OH)₂ → Ca(C₆H₁₁NHSO₃)₂ + 2H₂O

Explanation:

First, let's see the reactants for the first reaction and how they dissociate:

HC₆H₁₁NHSO₃ → H⁺ + C₆H₁₁NHSO₃⁻

BaCO₃ → Ba²⁺ + CO₃²⁻ (Barium is from group 2, so its cation has charge +2)

So, to form the products, the cation of one will join the anion of others. The amount of the cation will be the charge of the anion, and the amount of the anion will be the charge of the cation:

H⁺ + CO₃²⁻ → H₂CO₃

Ba²⁺ + C₆H₁₁NHSO₃⁻ → Ba(C₆H₁₁NHSO₃)₂

The reaction then is:

HC₆H₁₁NHSO₃ + BaCO₃ → Ba(C₆H₁₁NHSO₃)₂ + H₂CO₃

The number of elements must be the same on both sides, so the balanced equation is

2HC₆H₁₁NHSO₃ + BaCO₃ → Ba(C₆H₁₁NHSO₃)₂ + H₂CO₃

The treatment with H₂SO₄ will produce:

H₂SO₄ → 2H⁺ + SO₄⁻²

Ba(C₆H₁₁NHSO₃)₂ → Ba²⁺ + C₆H₁₁NHSO₃⁻

The balanced reaction will be then:

Ba(C₆H₁₁NHSO₃)₂ + H₂SO₄ → BaSO₄ + 2HC₆H₁₁NHSO₃

In the last step, HC₆H₁₁NHSO₃ will react with Ca(OH)₂

HC₆H₁₁NHSO₃ → H⁺ + C₆H₁₁NHSO₃⁻

Ca(OH)₂ → Ca²⁺ + 2OH⁻

The balance reaction will be:

2HC₆H₁₁NHSO₃ + Ca(OH)₂ → Ca(C₆H₁₁NHSO₃)₂ + 2H₂O

3 0
3 years ago
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