It is harder to remove an electron from fluorine than from carbon because the size of the nuclear charge in fluorine is larger than that of carbon.
The energy required to remove an electron from an atom is called ionization energy.
The ionization energy largely depends on the size of the nuclear charge. The larger the size of the nuclear charge, the higher the ionization energy because it will be more difficult to remove an electron from the atom owing to increased electrostatic attraction between the nucleus and orbital electrons.
Since fluorine has a higher size of the nuclear charge than carbon. More energy is required to remove an electron from fluorine than from carbon leading to the observation that; it is harder to remove an electron from fluorine than from carbon.
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Explanation:
The given following standard cell notation.
Mg(s) | Mg^2+ (aq) || Aq^+(aq) | Aq(s)
Oxidation:
....(1)
Magnesium metal by loosing 2 electrons is getting converted into magnesium cation. Hence, getting oxidized
Reduction:
...(2)
Silver ion by gaining 1 electrons is getting converted into silver metal. Hence, getting reduced.
Overall redox reaction: (1)+2 × (2)
Answer:
1.61 × 10⁶ kJ
Explanation:
The human burns energy so as to be healthy.
The amount of energy burnt per day by an adult human is 2 × 20³ kcal per day. Since there is 24 hours in a day, the amount of energy burnt per hour is 2 × 20³ × 24 = 48 × 20³ kcal per hour.
The conversion rate of kcal to kJ is 1 kcal = 4.184 kJ. Therefore converting the kcal per hour to kJ per hour gives:
48 × 20³ × 4.184 = 200.882 × 20³ kJ = 1.61 × 10⁶ kJ
