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UNO [17]
3 years ago
8

how to determine the aspects for core and valence electrons in a periodic table. How comes in some elements like cobalt the 3d i

s on the valence side and arsenic the 3d is on the core side.​
Chemistry
1 answer:
dusya [7]3 years ago
5 0

Answer:

See explanation

Explanation:

The electron configuration of an atom in an element determines the property of the atom. The core electrons are found inside the atom while the valence electrons are found on the outermost shell of the atom.

For cobalt, the outermost shell electron configuration is; [Ar] 3d7 4s2. The 3d7 and 4s2 are found in the valence shell of cobalt.

For arsenic, the electronic configuration is [Ar] 3d¹⁰ 4s² 4p³. The valence electrons are 4s2, 4p3. The 3d electrons are found inside the arsenic atom.

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Sufficient strong acid is added to a solution containing na2hpo4 to neutralize one-half of it. what will be the ph of this solut
Ivahew [28]
Assuming that the initial pH is pHi.
The initial concentration of [OH-] is
[OH]- = 10^(14 - pHi)

Since half of the Na2HPO4 is neutralized, the concentration of [OH-] will be reduced to half. The new pH will be
[OH-]/2 = 10^(14 - pHi)/2 = 10^(14 - pH)
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3 0
3 years ago
Ionic bonding gcse
cupoosta [38]
Group I and Group II have the same number of outermost electrons as you go down each group but the shells increase therefore as you go downward it becomes much easier to remove electrons because of its wide radius however group 7 and 6 have seven and six electrons in their outermost shell respectively. Therefore down the group it is much easier to attract electrons and across the period it is much harder because the number of electrons on the outermost shell increase
6 0
3 years ago
Easy Chem, Will Give brainliest
Crazy boy [7]

Answer:

3.94 L

Explanation:

From the question given above, the following data were obtained:

Mass of O₂ = 5.62 g

Volume of O₂ =?

Next, we shall determine the number of mole present in 5.62 g of O₂. This can be obtained as follow:

Mass of O₂ = 5.62 g

Molar mass of O₂ = 2 × 16 = 32 g/mol

Mole of O₂ =?

Mole = mass / molar mass

Mole of O₂ = 5.62 / 32

Mole of O₂ = 0.176 mole

Finally, we shall determine the volume of 5.62 g (i.e 0.176 mole) of O₂ at STP. This can be obtained as follow:

1 mole of O₂ occupied 22.4 L at STP.

Therefore, 0.176 mole of O₂ will occupy = 0.176 × 22.4 = 3.94 L at STP.

Thus 5.62 g (i.e 0.176 mole) of O₂ occupied 3.94 L at STP

5 0
3 years ago
If 8.00 mol of NH3 reacted with 14.0 mol of O2, how many moles of H20 will be produced?
otez555 [7]

Answer:

 12 moles of water will be produced

Explanation:

Given data:

Number of moles of NH₃ = 8.00 mol

Number of moles of O₂ = 14.0 mol

Number of moles of H₂O produced = ?

Solution:

Chemical equation:

4NH₃ + 7O₂        →      4NO₂ +6H₂O

Now we will compare the moles of reactant with product.

              NH₃           :           H₂O

               4               :            6

               8               :          6/4×8 = 12

             O₂               :              H₂O

              7                 :               6

              14               :           6/7×14 = 12

 12 moles of water will be produced.

3 0
3 years ago
All matter basically looks the same. Is this statement true or false?
kupik [55]

Answer

false

Explanation:

sorry I tbought i put false I hope I helped ....

3 0
3 years ago
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