Answer:
1. 80g
2. 1.188mole
Explanation:
1. We'll begin by obtaining the molar mass of CH4. This is illustrated below:
Molar Mass of CH4 = 12 + (4x1) = 12 + 4 = 16g/mol
Number of mole of CH4 from the question = 5 moles
Mass of CH4 =?
Mass = number of mole x molar Mass
Mass of CH4 = 5 x 16
Mass of CH4 = 80g
2. Mass of O2 from the question = 38g
Molar Mass of O2 = 16x2 = 32g/mol
Number of mole O2 =?
Number of mole = Mass /Molar Mass
Number of mole of O2 = 38/32
Number of mole of O2 = 1.188mole
Answer: No
Explanation: <em>Reactants</em> are the substances present at the beginning of a chemical reaction. In the burning of natural gas, for example, methane (CH4) and oxygen (O2) are the reactants in the chemical reaction. <em>Products </em>are the substances formed by a chemical reaction. In the burning of natural gas, carbon dioxide (CO2) and water (H2O) are the products formed by the reaction.
The correct answer is C, as if you do not understand something, it's always best to ask for help, especially when performing a sensitive procedure.
Answer: XF8
Explanation:
Empirical Formular shows the simplest ratio of elements in a compound.
Xe = 46.3% F = 53.7%
Divide the percentage composition of each element by the atomic mass.
Xe = 46.3/ 131.3 F= 53.7/ 19
= 0.353( approx) = 2.826 (approx)
Divide through with the smallest of the answers gotten in previous step.
Xe = 0.353 / 0.353 F = 2.826/ 0.353
= 1 = 8.0
Empirical formular = XF8
Answer:
The number of molecules in CH4, also known as methane, is merely 0.85 * 6.02210 * 10 ^ 23 (Avogadro's Number). This amounts to <em><u>approximately 5.1 * 10 ^ 23 molecules</u></em><u> with the correct number of significant figures</u>.
