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matrenka [14]
3 years ago
11

Explain why the biomass of foxes is less than the biomass of rabbits

Biology
2 answers:
dybincka [34]3 years ago
6 0

Answer:

I hope and this result Will serve you

iren2701 [21]3 years ago
4 0
There’s more rabbits. They reproduce quickly. Rabbits pregnancy take 30 days and foxes take 60 days. So foxes take twice as long.
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Based on the information in the table above, what Domain name should replace the X?
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The answer to the question is Eukarya
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3 years ago
Which patient situation indicates that a patient might be experiencing an increase in his perception of pain
saveliy_v [14]

Answer:

Explanation:

There are some signs and symptoms that a person may exhibit if they are in pain that can clue you in:

Facial grimacing or a frown.

Writhing or constant shifting in bed.

Moaning, groaning, or whimpering.

Restlessness and agitation.

Appearing uneasy and tense, perhaps drawing their legs up or kicking.

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The sun is the primary source
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5 0
3 years ago
A gene is involved in promoting limb development in humans. The gene is initially weakly activated during the limb induction pha
Anna [14]

Answer:

1. If the gene is weakly activated, it likely lacks repressive histone modifications, but may also lack the presence of histone marks associated with strong transcriptional activation such as acetylation.

When the gene is strongly activated, it likely lacks repressive marks (such as H3K9me2/3 and H3K27me3 - both examples of repressive histone methylation) and might possess some activating histone acetylation marks, such as H3K4ac, and active histone methylation such as H3K4me3

<em>An aside: The pattern and presence of different histone modifications would depend on the gene, but based on the fact that it is a developmental gene, I would assume that H3K27me3 and H3K4me3 are at play (these are part of the Polycomb/Trithorax system)</em>

<em />

After limb growth is complete, the gene is turned off. Repressive histone methylation marks would be associated with this state, such as the aforementioned H3K9me2/3 or H3K27me3.

2. Histone modifications are tightly linked to genome organisation. Histone methylation marks associated with repression such as H3K27me3 and H3K9me3 are associated with compact chromatin structures, which restrict the access of transcriptional machinery and other positive regulators. Conversely, histone marks associated with gene activation are associated with a more permissive chromatin environment that facilitates the binding of factors associated with gene expression. In the case of histone acetylation, the acetyl mark directly removes the positive charge of chromatin, relaxing its interaction with negatively charged DNA.

3. If the inappropriate activation of this gene caused a cancerous tumor, this gene would be referred to as an oncogene (or a proto-oncogene for the term before it is inappropriately activated).

Typically, there are two classes of genes that lead to cancer: tumor-suppressor genes and oncogenes. Tumor suppressor genes lead to cancer when their protective activity is reduced or demolished, leading to the production of cancer cells. Oncogenes lead to cancer when they become over active. Oncogenes are often genes associated positively with growth and proliferation, consistent with the gene in this example.

8 0
3 years ago
Consider the following hypothetical population and compute the statistical measures below: #births = 50,000; #deaths = 10,000; #
777dan777 [17]

Answer:

The birth rate refers to an average number of births in one year per thousand individuals in the population at mid-year.  

BR = (total birth in an annum / total population in mid year) * 1000

BR = (50000 / 1000000) * 1000 = 50

Death rate refers to an average number of death in an annum per thousand individuals in a population at mid year. Thus,  

DR = (total death / total population in mid year) * 1000

DR = (10000 / 1000000) * 1000 = 10

Annual population growth rate or APGR is calculated as:  

APGR = (Birth rate - Death rate) / Death rate

APGR = (50 - 10) / 10 = 4.0 %

Doubling time is the whole sum time needed for a population to get double in size. It is calculated as DT = ln (2) / growth rate

70 / 4.0 = 17.5 years

Thus, population will get double in 17.5 years.  

Adjusted (true) growth rate is equal to APGR + (NMR / Death rate)

And NMR = [(immigrants -emigrants) / total population] * 1000

NMR = [(5000 - 20000) / 1000000] * 1000 = -15

Thus, Adjusted (True) growth rate = 4.0 + (-15 /10) = -6%

The adjusted (true) doubling time = ln (2) / Adjusted growth rate  

= 70 / -6 = -11.66

This negative sign shows that it will never get double in such situation.  

5 0
3 years ago
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