Answer:
Option D- frequency of the heterozygous qenotype
Explanation:
In the Hardy-Weinberg equilibrium , 2pq stands for the genotype frequency of heterozygotes (Aa) in a population at the state of equilibrium. dominant homozygotes (AA) is represented by the p-square and q- square represents the recessive homozygotes (aa) frequency. p represents the allele frequency of A Allele and q stands for the allele frequency of the allele a. Summation of the terms gives an equal to 1(100%). The sum of all of these terms is always equal to due to the fact that the 3 frequencies in the equation are the available or possible allele combinations.
Hardy-Weinberg is relevant for it helps us in comparison of a population's actual genetic structure as time goes on along with the genetic structure we are to get if really population was in Hardy-Weinberg equilibrium state that is population was not evolving.
Prokaryotic cells do not have membrane bound organelles. Eukaryotic cells do have membrane bound organelles. The membrane controls movement in and out of the cell. ... The cytoplasm fills the space between the nucleus and the cell membrane.
Answer:
Mutation.
Explanation:
Mutation in the organism's DNA that is passed on to the offspring is that main cause of heritable phenotypic change in some members of a population that reproduces asexually. Repeated exposure of Plasmodium that is sensitive to artesunate strain to increasing dosage of artesunate led to the development of resistance in plasmodium because the genetic mutation occur in the plasmodium that provide resistance against artesunate.
To make the risk of getting cancer again and not surviving clear to everyone
Answer:
There are 40 electrons and protons and 50 neutrons
Explanation:
