Answer:
I believe it's the third and fourth answers.
Step-by-step explanation:
Answer:
Here we can use the relationship:
Distance = time*speed.
When Jose walks, his speed is 4 mph.
Then if he walks for X hours, the distance that he will travel is:
D = 4mph*X
When Jose runs, his speed is 8mph.
Then if he runs for T hours, the distance that he will travel is:
D´ = 8mph*Y
And we know that he travels in total 20 miles, then we must have that:
D + D´= 20mi
This leads to:
4mph*X + 8mph*Y = 20mi
Where X is the time that he walked, and Y is the time that he runed.
Then the equation that represents the different amounts of times that Jose runs and walks is:
4mph*X + 8mph*Y = 20mi
Where we can not really find the solutions for Y and X, because there is only one equation and two variables.
Start from
Multiply both sides by 2:
Which you can rewrite as
|x-4| <3
=>. x-4<3 or -(x-4)<3
=>. x-4<3 or x+4>3
=>. x<7 or x>1
So solution is x>1 & x<7. =x€(1,7)
Hope it helps...
Regards,
Leukonov/Olegion.
